The derivative of f(x) at x=3 is 2x=6 approaching from the left side (apply power rule to y=x^2). The derivative of f(x) at x=3 is m approaching from the right side. In order for the function to be differentiable, the limit of derivative at x=3 must be the same approaching from both sides, so m=6. Then, x^2=mx+b at x=3, plug in m=6, 9=18+b, so b=-9.
Answer: -1/343
Step-by-step explanation:
-7(-7)^-4
First, re-write as positive exponents:
-7(-1/7^4)
Next, simplify:
-1/7^3 (you can simplify using exponent rules)
Simplify 7^3 :
7(7)(7)
49(7)
343.
Insert to original expression:
-1/343.
As x increases by 1 the value of f(x) doubles so we need 2^x
When x = 0 the value of f(x) = 3
The correct answer is f(x) = 3(2^x). [the top option]
Answer:
(5,2)
Step-by-step explanation:
i am unsure of what your question is but if you want the point of intersection of the two lines its (5,2)
