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joja [24]
3 years ago
14

How are the inner planets different from the outer planets?

Physics
2 answers:
uranmaximum [27]3 years ago
5 0

Answer:

the outer planets r full of gas,while the inner planets aren't

Explanation:

Zepler [3.9K]3 years ago
3 0

The inner planets are closer to the sun, rockier and smaller. The outer planets are further from the sun, bigger and consisting primarily of gas.

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A horizontal spring with stiffness 0.4 N/m has a relaxed length of 11 cm (0.11 m). A mass of 21 grams (0.021 kg) is attached and
riadik2000 [5.3K]

Answer:

0.6983 m/s

Explanation:

k = spring constant of the spring = 0.4 N/m

L₀ = Initial length = 11 cm = 0.11 m

L = Final length = 27 cm = 0.27 m

x = stretch in the spring = L - L₀ = 0.27 - 0.11 = 0.16 m

m = mass of the mass attached = 0.021 kg

v = speed of the mass

Using conservation of energy

Kinetic energy of mass = Spring potential energy

(0.5) m v² = (0.5) k x²

m v² = k x²

(0.021) v² = (0.4) (0.16)²

v = 0.6983 m/s

5 0
4 years ago
For small angles, does the pendulum's period of oscillation depend on initial angular displacement from equilibrium? Explain.
aksik [14]

Answer:

No, the pendulum's period of oscillation does not depend on initial angular displacement.

Explanation:

Given that,

For small angle, the pendulum's period of oscillation depend on initial angular displacement from equilibrium.

We know that,

The time period of pendulum is defined as

T=2\pi\sqrt{\dfrac{l}{g}}

Where, l = length of pendulum

g = acceleration due to gravity

So, The time period of pendulum depends on the length of pendulum and acceleration due to gravity.

It does not depend on the initial angular displacement.

Hence, No, the pendulum's period of oscillation does not depend on initial angular displacement.

6 0
4 years ago
Jeremiah rides his bicycle 4 miles in 30 minutes. If he maintains this rate, how far will he ride in 3 hours?
Triss [41]

Answer:

24 miles.

Explanation:

3 hours=180 minutes

180÷30=6

6x4=24

8 0
2 years ago
A water wave has a wavelength of 204 m and a frequency of 0.5 Hz. How far does it travel in 1 s?
Zigmanuir [339]

Answer:

c = 204 x 5 = 1020 m/s so it travels 1020 meters in 1 second.

Explanation:

7 0
3 years ago
Normal conversation in an office produces a decibel rating of 50 db. how many identical voices could you add without exceeding a
o-na [289]
<span>100000
    Decibel (dB) is a logarithmic scale of power. Depending upon if you're looking for power, or root power a change in the power by a factor of 10 will be 10dB, or 20dB. Since this question is asking about "sound intensity" it's looking for a power factor, not a root-power factor (which would be the case for sound pressure). So we're looking for a 50 dB increase (100 dB - 50 dB) = 50 dB which means that we're wanting 10^5 = 100,000 times as much power. Assuming each identical voice contributes the same amount of power, you'd have 100,000 (one hundred thousand) voices talking at once for a sound intensity of 100 dB.</span>
3 0
3 years ago
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