Answer:
0.6983 m/s
Explanation:
k = spring constant of the spring = 0.4 N/m
L₀ = Initial length = 11 cm = 0.11 m
L = Final length = 27 cm = 0.27 m
x = stretch in the spring = L - L₀ = 0.27 - 0.11 = 0.16 m
m = mass of the mass attached = 0.021 kg
v = speed of the mass
Using conservation of energy
Kinetic energy of mass = Spring potential energy
(0.5) m v² = (0.5) k x²
m v² = k x²
(0.021) v² = (0.4) (0.16)²
v = 0.6983 m/s
Answer:
No, the pendulum's period of oscillation does not depend on initial angular displacement.
Explanation:
Given that,
For small angle, the pendulum's period of oscillation depend on initial angular displacement from equilibrium.
We know that,
The time period of pendulum is defined as
Where, l = length of pendulum
g = acceleration due to gravity
So, The time period of pendulum depends on the length of pendulum and acceleration due to gravity.
It does not depend on the initial angular displacement.
Hence, No, the pendulum's period of oscillation does not depend on initial angular displacement.
Answer:
c = 204 x 5 = 1020 m/s so it travels 1020 meters in 1 second.
Explanation:
<span>100000
Decibel (dB) is a logarithmic scale of power. Depending upon if you're looking for power, or root power a change in the power by a factor of 10 will be 10dB, or 20dB. Since this question is asking about "sound intensity" it's looking for a power factor, not a root-power factor (which would be the case for sound pressure). So we're looking for a 50 dB increase (100 dB - 50 dB) = 50 dB which means that we're wanting 10^5 = 100,000 times as much power. Assuming each identical voice contributes the same amount of power, you'd have 100,000 (one hundred thousand) voices talking at once for a sound intensity of 100 dB.</span>
