Answer:
t=67.7s
Explanation:
From this question we know that:
Vo = 6m/s
a = 1.8 m/s2
D = 1500m
And we also know that:
Replacing the known values:
Solving for t we get 2 possible answers:
t1 = -44.3s and t2 = 67.7s Since negative time represents an instant before the beginning of the movement, t1 is discarded. So, the final answer is:
t = 67.7s
An astronomical unit is the measure of the center of the Earth to the center of the sun.
Because our solar system is so vast, using mere miles is ridiculous, because they are too small to be helpful and the numbers will be in the billions. Astronomical units make it easier to think in small amounts.
Hope this helps :)
Answer:
2.56 m/s²
Explanation:
A standing wave is produced in the wire, its frequency f = n/2l√(T/μ). For the fundamental frequency, n = 1.
f = 1/2l√(T/μ)
where l = length of wire = 1.60 m, T₁ = tension in wire = weight of object = m₁g (neglecting wires mass), m₁ = mass of object = 3.00 kg, g = acceleration due to gravity on the small planet, μ = linear density of wire = m₀/l , m₀= mass of wire = 4.30 g = 0.0043 kg and f = 1/T where T = period of pulse = 59.9 ms = 0.0599 s
f = 1/2l√(T₀/μ) = 1/T ⇒ T₁ = 4l²μ/T²
m₁g = 4l²μ/T²
g = 4l²μ/m₁T² = 4l²m₀/l/m₁T² = 4lm₀/m₁T²
g = 4lm₀/m₁T² = 4 × 1.60 × 0.0043/(3.00 × 0.0599²) = 2.56 m/s²
Answer:
0.6 pound.
Explanation:
From the question given above:
Julie applies 2.67 Newton (N) of force down onto the table.
Hence, we can obtain the force in pound applied by Julie on the table as follow:
Recall:
1 N = 0.225 pound
Therefore,
2.67 N = 2.67 × 0.225
2.67 N = 0.6 pound
Therefore, the force in pound applied by Julie on the table is 0.6 pound
Answer:
P₁ = 1.0 atm
V₁ = 35 L
P₂ = 0.75 atm
Formula:
P₁V₁ = P₂V₂
Solution:
P₁V₁ = P₂V₂
V₂ = P₁V₁ / P₂
V₂ = (1.0 atm)(35 L) / 0.75 atm
V₂ = 47 L
Final Answer:
V₂ = 47 L
