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Naya [18.7K]
3 years ago
10

Please answer this in two minutes

Mathematics
1 answer:
Fudgin [204]3 years ago
3 0

Answer:

R = 21.8° to the nearest tenth

Step-by-step explanation:

To find Angle R we use tan

tan ∅ = opposite / adjacent

From the question

The opposite is 2

The adjacent is 5

So we have

tan R = 2/5

R = tan-¹ 2/5

<h3>R = 21.8° to the nearest tenth</h3>

Hope this helps you

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A café owner is designing a new menu and wants to include a decorative border around the outside of her food listings. Due to th
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The 13-in. by 9-in. rectangle where the food listings fit has an area of 13 in. * 9 in. = 117 in.^2

Adding 48 in.^2 for the border, the total area of the menu with the border will be 117 in.^2 + 48 in.^2 = 165 in.^2

The border has to have uniform width around the menu. We need to find the width of the border. Let the border be x inches wide. Then since you have a border at each of the 4 sides, the border will add 2x to the length of the rectangle and 2x to the width of the rectangle. The menu will have a length of 2x + 13 and a width of 2x + 9. The area of the larger rectangle must by 165 in.^2. The area of a rectangle is length times width, so we get our equation:

(2x + 13)(2x + 9) = 165

Multiply out the left side (use FOIL or any other method you know):

4x^2 + 18x + 26x + 117 = 165

4x^2 + 44x + 117 = 165

4x^2 + 44x - 48 = 0

Divide both sides by 4.

x^2 + 11x - 12 = 0

Factor the left side.

(x + 12)(x - 1) = 0

x + 12 = 0 or x - 1 = 0

x = -12 or x = 1

The solution x = -12 is not valid for our problem because the width of a border cannot be a negative number. Discard the negative solution.

The solution is x = 1.

Answer: The border is 1 inch wide.

Check. Add 2 inches to the length and width of the food listings rectangle to get 15 inches by 11 inches. A = 15 in. * 11 in.= 165 in.^2. Now subtract the area of the border, 48 in.^2, 165 in.^2 = 48 in.^2 = 117 in.^2, and you get the area of the 13-in. by 9-in. rectangle. This shows that our solution is correct.

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Where is the scale image?
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\sf \large \underbrace{ \underline{Understanding  \: the  \: Question}}

This can be considered as a very easy Question where you have to find the value of √85 and √86 upto 2 decimal places then we could find it easily.

Let's start!

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Now it is obvious that 9.25 lies between √85 and √86.

\sf \large \underbrace{ \underline{Additional \:  information}}

What are rational no.?

Any pair of numbers which is in the form of p/q where p and q are integers and p and q are co-prime is called rational number.

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