Answer:
D.
Step-by-step explanation:
You know that 0.25 went to 2.00. That means that it's a 1.75 jump. In order to jump the other two prices up and keep the ratio the same, you must also jump them 1.75.
0.05 + 1.75 = 1.80
0.10 + 1.75 = 1.85
To double check the ration we can look back on the original. 0.05 to 0.10 is a scale of 0.05. 0.10 to 0.25 is a scale of 0.15
Then we look at our new one. 1.80 to 1.85 is a scale of 0.05. 1.85 to 2.00 is a scale of 0.15.
The ratios stayed the same, so this is the correct answer.
I hope this helped :)
Answer:
1/5
Step-by-step explanation:
1 pack of paper/ 5 groups
or all three groups
3/5
The domain are all valid values for x (the independent variable) that can be used in an equation.
We have to look at any potential values of x which won't work. Easily put: in algebra, just look for values of x which cause either division by zero, or the square root of negative numbers.
A couple of examples:
y=2x+4
You can insert any negative or positive value, or zero, for x and get a valid equation. Therefore the domain is the set of all real numbers. Answers are usually written as:
x: {R}, or simply 'all real numbers'.
what about y=2/(x-1)
In this equation, x appears in the denominator. If x-1=0, then division by zero would occur.
Solve: x-1≠0
x≠1
In set notation:
x: (-∞,1)∪(1,∞)
Parentheses are next to the 1, as the domain comes up to 1, but does not include 1.
Read left to right, the domain is "negative infinity to 1, exclusive, in union with 1 to positive infinity"
3 should be added to the tiles
Answer:
1. b ∈ B 2. ∀ a ∈ N; 2a ∈ Z 3. N ⊂ Z ⊂ Q ⊂ R 4. J ≤ J⁻¹ : J ∈ Z⁻
Step-by-step explanation:
1. Let b be the number and B be the set, so mathematically, it is written as
b ∈ B.
2. Let a be an element of natural number N and 2a be an even number. Since 2a is in the set of integers Z, we write
∀ a ∈ N; 2a ∈ Z
3. Let N represent the set of natural numbers, Z represent the set of integers, Q represent the set of rational numbers, and R represent the set of rational numbers.
Since each set is a subset of the latter set, we write
N ⊂ Z ⊂ Q ⊂ R .
4. Let J be the negative integer which is an element if negative integers. Let the set of negative integers be represented by Z⁻. Since J is less than or equal to its inverse, we write
J ≤ J⁻¹ : J ∈ Z⁻
