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asambeis [7]
3 years ago
13

Find the midpoint of R(2,2) and S(-3,6)

Mathematics
2 answers:
r-ruslan [8.4K]3 years ago
5 0

Answer:

M=(-\frac{1}{2},4)

Step-by-step explanation:

The midpoint formula is given by:

M=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

Let (2,2) be x₁ and y₁ and let (-3,6) be x₂ and y₂. Therefore:

M=(\frac{2+-3}{2},\frac{2+6}{2})

Simplify:

M=(-\frac{1}{2},\frac{8}{2})\\M=(-\frac{1}{2},4)

musickatia [10]3 years ago
3 0

Answer: (-0.5, 4)

Step-by-step explanation:

Midpoint formula: (\frac{x1+x2}{2} ,\frac{y1+y2}{2} )

(x1, x2)=(2, -3)

(y1, y2)=(2, 6)

-----------------------------------------------

 (\frac{x1+x2}{2} ,\frac{y1+y2}{2} )

=(\frac{2-3}{2} ,\frac{2+6}{2} )

=(\frac{-1}{2} ,\frac{8}{2} )

=(-0.5, 4)

Hope this helps!! :)

Please let me know if you have any question or need further explanation

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The perimeter of a triangle is 42 inches one side measures 18 inches the shortest side measures x inches the longest side measur
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By writing an equation you can easily solve this:

18+ X + 4X - 1 = 42
•we need the answer to 4X-1

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4 0
3 years ago
42:28
gogolik [260]

Answer:

The statements about arcs and angles that are true in the figure are;

1) ∠EFD ≅ ∠EGD

2) \overline{ED}\cong \overline{FD}

3) mFD = 120°

Step-by-step explanation:

1) ∠ECD + ∠CEG + ∠CDG + ∠GDE = 360° (Sum of interior angle of a quadrilateral)

∠CEG = ∠CDG = 90° (Given)

∠GDE = 60° (Given)

∴ ∠ECD = 360° - (∠CEG + ∠CDG + ∠GDE)

∠ECD = 360° - (90° + 90° + 60°) = 120°

∠ECD = 2 × ∠EFD (Angle subtended is twice the angle subtended at the circumference)

120° = 2 × ∠EFD

∠EFD = 120°/2 = 60°

∠EFD ≅ ∠EGD

∠ECD = 120°

∠EGD = 60°

∴∠EGD ≠ ∠ECD

2) Given that arc mEF ≅ arc mFD

Therefore, ΔECF and ΔDCF are isosceles triangles having two sides (radii EC and CF in ΔECF and radii EF and CD in ΔDCF

∠ECF = mEF = mFD = ∠DCF (Given)

∴ ΔECF ≅ ΔDCF (Side Angle Side, SAS, rule of congruency)

\\ \overline{EF}\cong \overline{FD} (Corresponding Parts of Congruent Triangles are Congruent, CPCTC)

∠FED ≅ ∠FDE (base angles of isosceles triangle)

∠FED + ∠FDE + ∠EFD = 180° (sum of interior angles of a triangle)

∠FED + ∠FDE = 180° - ∠EFD = 180° - 60° = 120°

∠FED + ∠FDE = 120° = ∠FED + ∠FED (substitution)

2 × ∠FED  = 120°

∠FED = 120°/2 = 60° = ∠FDE

∴ ∠FED = ∠FDE = ∠EFD =  60°

ΔEFD  is an equilateral triangle as all interior angles are equal

\\ \overline{EF}\cong \overline{FD}\cong \overline{ED} (definition of equilateral triangle)

\overline{ED}\cong \overline{FD}

3) Having that ∠EFD = 60° and ∠CFE = ∠CFD (CPCTC)

Where, ∠EFD = ∠CFE + ∠CFD (Angle addition)

60° = ∠CFE + ∠CFD = ∠CFE + ∠CFE (substitution)

60° = 2 × ∠CFE

∠CFE =60°/2 = 30° = ∠CFD

\overline{CF}\cong \overline{CD} (radii of the same circle)

ΔFCD is an isosceles triangle (definition)

∠CFD ≅ ∠CDF (base angles of isosceles ΔFCD)

∠CFD + ∠CDF + ∠DCF = 180°

∠DCF = 180° - (∠CFD + ∠CDF) = 180° - (30° + 30°) = 120°

mFD = ∠DCF (definition)

mFD = 120°.

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Amiraneli [1.4K]
<h2>Answer:</h2>

Figure B

<h2>Step-by-step explanation:</h2>

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To find the side length of each square, you have to square root the area of each square. This means that Figure A has side lengths of 3, 6 and 8 units. Figure B has side lengths of 5, 12 and 13 units.

In Figure A, if the triangle is right-angled, the equation 3^2 + 6^2 = 8^2 must be correct. 9 + 36 = 45. 45 is not equal to 64, so the triangle is not right-angled.

In Figure B,  if the triangle is right-angled, the equation 5^2 + 12 ^2 = 13^2 must be correct. 25 + 144 = 169. 169 is 13 squared, so the triangle is right-angled.

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8 0
3 years ago
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