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asambeis [7]
3 years ago
13

Find the midpoint of R(2,2) and S(-3,6)

Mathematics
2 answers:
r-ruslan [8.4K]3 years ago
5 0

Answer:

M=(-\frac{1}{2},4)

Step-by-step explanation:

The midpoint formula is given by:

M=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

Let (2,2) be x₁ and y₁ and let (-3,6) be x₂ and y₂. Therefore:

M=(\frac{2+-3}{2},\frac{2+6}{2})

Simplify:

M=(-\frac{1}{2},\frac{8}{2})\\M=(-\frac{1}{2},4)

musickatia [10]3 years ago
3 0

Answer: (-0.5, 4)

Step-by-step explanation:

Midpoint formula: (\frac{x1+x2}{2} ,\frac{y1+y2}{2} )

(x1, x2)=(2, -3)

(y1, y2)=(2, 6)

-----------------------------------------------

 (\frac{x1+x2}{2} ,\frac{y1+y2}{2} )

=(\frac{2-3}{2} ,\frac{2+6}{2} )

=(\frac{-1}{2} ,\frac{8}{2} )

=(-0.5, 4)

Hope this helps!! :)

Please let me know if you have any question or need further explanation

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Let f(x) = xe^-x+ ce^-x, where c is a positive constant. For what positive value of c does f have an absolute
Illusion [34]

Answer:

c=6

Step-by-step explanation:

The absolute maximum of a continuous function f(x) is where f'(x)=0. Therefore, we must differentiate the function and then set x=-5 and f'(x)=0 to determine the value of c:

f(x)=xe^{-x}+ce^{-x}

f'(x)=-xe^{-x}+e^{-x}-ce^{-x}

0=-(-5)e^{-(-5)}+e^{-(-5)}-ce^{-(-5)}

0=5e^{5}+e^{5}-ce^{5}

0=e^5(5+1-c)

0=6-c

c=6

Therefore, when c=6, the absolute maximum of the function is x=-5.

I've attached a graph to help you visually see this.

7 0
2 years ago
I need to know this please help me
lara [203]

Answer:

x is 16

Step-by-step explanation:

Multiply the 2/5 by 8/8 and you should get 16/40

Hope this helped!

5 0
3 years ago
BRAINIEST TO WHOEVER RIGHT
adoni [48]

Answer:

i know b only Sorry hope this helps tho

Step-by-step explanation:

its 4 because each space is 25% no matter how big or small it is. so if you land on -9 to -5 thats 25% and to -2 thats another 25% total 50% its asking for 75% so you go one more which lands on 4 making it 75%

5 0
3 years ago
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A scientist removed a sample of 39.1 grams of a chemical from a container. The sample was 5 3/4 grams less than 3/10 of the tota
Oksanka [162]

The first thing we must do for this case is to define variables:

x: the total mass of the chemical in the container

y: a sample of a chemical from a container

We have the following equation:

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Then, for y = 39.1 we have:

39.1 = (3/10) x - 5 3/4

Clearing x:

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(3/10) x = 44.85

x = (10/3) * (44.85)

x = 149.5 grams

Answer:

the total mass in grams of the chemical in the container before the scientist removed the sample of 39.1 grams was:

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3 years ago
A boy flying a kite lets out 300 feet of string. The height of the kite is 185 feet. What is the angle
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Answer:

The string, the height and the ground form a right triangle

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38.073 degrees

Step-by-step explanation:

4 0
3 years ago
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