Area of Triangle:
A = 1/2 bh = 1/2 (5)(12) = 30 m^2
Area of semicircle:
A = 1/2 π r^2 = 1/2 π 6^2 = 18<span>π m^2
Area of figure = </span>Area of semicircle + Area of Triangle
Area of figure = 18π + 30 m^2
Answer is C.
18π + 30 m^2
Y-y
——-
X-x
21-9=12
5-(-1) =6
So the answer is D
Answer:
neither
Step-by-step explanation:
find the slopes of FG and HJ using the slope formula (y_2-y_1)/(x_2-x_1)
FG: (-1+3)/(-2-1)=2/-3=-2/3
HJ: (3-0)/(6-5)=3/1=3
perpendicular lines have slopes that are the negative reciprocal of each other. -2/3's negative reciprocal is 3/2 which isn't 3. the lines aren't parallel or perpendicular
It’s 75! 65+40= 105 then 180-105= 75
Answer:
no but you can have my gm/ail
Step-by-step explanation:
