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Effectus [21]
4 years ago
10

When sulfur emitted by smokestacks combines with moisture in the atmosphere to form acids that are spread by the wind, ____ resu

lts.
a. wet pollution
b. air pollution
c. acid rain
d. fire
e. emissions
Chemistry
1 answer:
kari74 [83]4 years ago
5 0

Answer:

The correct option is: c. acid rain

Explanation:

Acid rain refers to the precipitation that has an <u>acidic pH</u>. This type of precipitation is harmful as it has high hydrogen ion concentration.

The <u>harmful emissions such as sulfur dioxide and nitrogen oxide</u>, that are present in the Earth's atmosphere and <u>transported by the air and wind, react with the water molecules</u> during the precipitation to produce <u>acidic rain.</u>

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Which an element that exist into two form​
Brut [27]

Answer:

Sulphur

Explanation

Rhombic and monoclinic sulphur are its allotropic forms

3 0
3 years ago
A student is studying the boiling points of six different liquids and finds results with consistently higher boiling points than
almond37 [142]

Answer:

Large molecules tend to have greater boiling points because the London dispersion forces are stronger within.

Explanation:

4 0
3 years ago
2.25 g/ml at 700mmHg, 200 C. Find molar mass of gas.
Harrizon [31]

Answer:

Molar mass = 94972.745 g/mol

Explanation:

Given data:

Density = 2.25 g/ml

Pressure = 700 mmHg

Temperature = 200°C

Molar mass = ?

Solution:

Density = 2.25 g/ml (2.25×1000 = 2250 g/L)

Pressure = 700 mmHg (700/760 = 0.92 atm)

Temperature = 200°C (200+273 = 473K)

Formula:

d = PM/RT

M = dRT/P

M = 2250 g/L × 0.0821 atm.L /mol.K ×  473K / 0.92 atm

M = 87374.93 g/mol / 0.92

M = 94972.745 g/mol

6 0
4 years ago
A force of 2,500 pounds drags a truck 30 feet in 1/2 minute.
scoray [572]
The right subject for this question is physics.

To calculate the work you use the formula:

Work = force * displacement

Work = 2500 pounds * 30 feet = 75,000 pounds - feet



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power = work / time

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3 0
3 years ago
How many moles are in 1.2x10^3 grams of ammonia(NH3) ?
miskamm [114]

Answer : The number of moles present in ammonia is, 70.459 moles.

Solution : Given,

Mass of ammonia = 1.2\times 10^3g

Molar mass of ammonia = 17.031 g/mole

Formula used :

\text{Moles of }NH_3=\frac{\text{ given mass of }NH_3}{\text{ molar mass of }NH_3}

\text{Moles of }NH_3=\frac{1.2\times 10^3g}{17.031g/mole}=70.459moles

Therefore, the number of moles present in ammonia is, 70.459 moles.

5 0
3 years ago
Read 2 more answers
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