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RoseWind [281]
3 years ago
15

How many grams of O2 are needed in a reaction that produces 78.2 g of Na2O?

Chemistry
1 answer:
elena-14-01-66 [18.8K]3 years ago
7 0
Do you have the reaction and coefficients?
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if the atomic number of neon is 10, how many dots would be needed to represent the outer electrons for an atom of neon in an ele
Neko [114]

Answer: 8 dots would be needed to represent the outer electrons for an atom of neon in an electron dot diagram.

Explanation:

Electron-dot diagram is also known as Lewis-dot structure. It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.  The valence electrons are represented by 'dot'.

As atomic number of neon is 10 and we know that neon has 10 electrons with electronic configuration of 2,8 and thus has '8' valence electrons.

Therefore, the total number of valence electrons is 8 and 8 dots would be needed to represent the outer electrons for an atom of neon in an electron dot diagram.

5 0
4 years ago
A characteristic that describe a plant that can make its own food is
umka21 [38]

Answer:

Photosynthesis

this is correct

7 0
3 years ago
During a chemical reaction, how do the substances that form differ from the substances that react?
cricket20 [7]

Answer:

A physical change, such as a state change or dissolving, does not create a new substance, but a chemical change does. ... In a chemical reaction, reactants contact each other, bonds between atoms in the reactants are broken, and atoms rearrange and form new bonds to make the products.

Explanation:

8 0
3 years ago
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Why is an intensive property different from an extensive property
damaskus [11]

Answer:

check out this website,it might help.

Explanation:

https://courses.lumenlearning.com/boundless-chemistry/chapter/physical-and-chemical-properties-of-matter/

Im really not the smartest in the world.

<em><u>Website was not made by me, im just a lazy potat0.</u></em>

6 0
3 years ago
calculate the grams of oxygen gas present in a 2.50 L sample kept at 1.66 atm pressure and a temperature of 10.0 C
Ahat [919]

Answer:

5.72 grams of O₂ are present in the sample

Explanation:

Let's calculate the moles of O₂ by the Ideal Gases Law.

P . V = n . R . T

1.66 atm . 2.50L = n . 0.082 . 283K

(1.66 atm . 2.50L) / 0.082 . 283K = n

0.179 mol = n

Molar mass O₂ = 32 g/m

Mol . molar mass = mass → 0.179 m . 32g/m = 5.72 g

8 0
3 years ago
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