F = MA
30,000 kg * 1.5 m/s^2 = 45,000 N
Answer: A = y/cos32
That is the amplitude A in terms of the displacement y.
Explanation: Since the displacement in the question In the question is the same in both direction, it is a Simple Harmonic Motion problem. In s.h.m the amplitude of displacement A is related to the displacement itself y by this simple equation
y = A* cos(theta)
So, A = y/cos(theta)
A = y/cos32.
If the magnitude of the displacement y is given, you just substitute in.
I think its10/81 not sure
Answer:
In a simplest terms,
temperature is how hot or cold an object is, while heat is the energy that flows from a hotter object to cooler one
For uniform acceleration (or deceleration in this case), you use the formula:
Vf = Vi + at
Vi = 22 m/s
Vf = 0 (coming to a stop)
t = 5 sec
Plugging everything into the formula gives you:
0 = 22 + 5a
-22 = 5a
a = -22/5 or -4.4 m/s^2
Hope this helps!