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insens350 [35]
4 years ago
9

Who discovered electromagnetic induction?

Physics
1 answer:
allsm [11]4 years ago
7 0

Answer: Electromagnetic induction was discovered by Michael Faraday

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a ball is thrown straight up it passes a 2.00 m high window 7.5 meters off the ground on its path up it takes 1.3 s to go past t
Svet_ta [14]
Let's say the velocity at the bottom of the window was "v."
s = v*t + ½at²
2 m = v * 1.3s - 4.9m/s² * (1.3s)² = v * 1.3s - 8.3 m
v = 10.3m / 1.3s = 7.9 m/s

Then the initial speed was
V = √(v² + 2as) = √(7.9m/s² + 2 * 9.8m/s² * 7.5m) = 14 m/s ◄ initial velocity
(after rounding to 2 digits from 14.5 m/s).
8 0
3 years ago
Particles q1, q2, and q3 are in a straight line.
natima [27]

The net force on q2 will be 1.35 N

A force in physics is an effect that has the power to alter an object's motion. A mass-containing object's velocity can vary, or accelerate, as a result of a force. Intuitively, a push or a pull can also be used to describe force. Being a vector quantity, a force has both magnitude and direction.

Given Particles q1, q2, and q3 are in a straight line. Particles q1 = -5.00 x 10-6 C,q2 = +2.50 x 10-6 C, and q3 = -2.50 x 10-6 C. Particles q₁ and q2 are separated by 0.500 m. Particles q2 and q3 are separated by 0.250 m.

We have to find the net force on q2

At first we will find Force due to q1

F = 9 × 10⁹ × 5 × 10⁻⁶ × 2.5 × 10⁻⁶ / 0.5²

F = 450 × 10⁻³

F₁ = 0.45 N (+)

Now we will find Force due to q2

F = 9 × 10⁹ × 5 × 10⁻⁶ × 2.5 × 10⁻⁶ / 0.25²

F = 1800 × 10⁻³

F₂ = 1.8 N (-)

So net force (F) will be

F = F₂ - F₁

F = 1.8 - 0.45

F = 1.35 N

Hence the net force on q2 will be 1.35 N

Learn more about force here:

brainly.com/question/25573309

#SPJ10

8 0
2 years ago
A body of mass 400 kg is suspended at a lower end of a light vertical chain and is being pulled up vertically. Initially the bod
yKpoI14uk [10]

Answer:31.62 m/s

Explanation:

Given

mass of body m=400 kg

Pull on chain is F_1=6000g N=60 kN

Pull get smaller at the rate of F_2=360g N/m

Net Upward Force F=6000 g-360 g\times 10=24 kN

net acceleration a=\frac{F}{m}

a=\frac{24\times 1000}{m}

a=\frac{24000}{400}

a=60 m/s^2

but g is acting downward

a_{net}=a-g=60-10=50 m/s^2

using v^2-u^2=2 as

here initial velocity is zero

v^2=2\times 50\times 10

v=31.62 m/s

7 0
4 years ago
1:What kind of energy does your body use to keep you warm.
Zigmanuir [339]

Answer:

1. thermal energy

2. Batteries and coal

4. energy conversion

3 0
3 years ago
A jogger jogs around a circular track with a diameter of 275 m in 14.0 minutes. what was the jogger's average speed in m/s?
Pie

The jogger's average speed 1.03 m/s

<h3>The Speed and the Velocity of a Particle in a Circle</h3>

The speed of a particle is a circle will always be constant while the velocity will not. That is, velocity varies.

Given that a jogger jogs around a circular track with a diameter of 275 m in 14.0 minutes. First convert the minutes to seconds

Given parameters are;

  • Diameter = 275 m
  • Radius r = D/2 = 137.5 m
  • Time t = 14 minutes = 14 x 60s = 840 s

Speed V = 2πr ÷ t

V = ( 2 × π × 137.5 )  ÷ 840

V = 863.9 / 840

V = 1.028 m/s

Therefore, the jogger's average speed 1.03 m/s approximately

Learn more about Circular Motion here: brainly.com/question/20905151

#SPJ1

5 0
2 years ago
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