Let's say the velocity at the bottom of the window was "v."
s = v*t + ½at²
2 m = v * 1.3s - 4.9m/s² * (1.3s)² = v * 1.3s - 8.3 m
v = 10.3m / 1.3s = 7.9 m/s
Then the initial speed was
V = √(v² + 2as) = √(7.9m/s² + 2 * 9.8m/s² * 7.5m) = 14 m/s ◄ initial velocity
(after rounding to 2 digits from 14.5 m/s).
The net force on q2 will be 1.35 N
A force in physics is an effect that has the power to alter an object's motion. A mass-containing object's velocity can vary, or accelerate, as a result of a force. Intuitively, a push or a pull can also be used to describe force. Being a vector quantity, a force has both magnitude and direction.
Given Particles q1, q2, and q3 are in a straight line. Particles q1 = -5.00 x 10-6 C,q2 = +2.50 x 10-6 C, and q3 = -2.50 x 10-6 C. Particles q₁ and q2 are separated by 0.500 m. Particles q2 and q3 are separated by 0.250 m.
We have to find the net force on q2
At first we will find Force due to q1
F = 9 × 10⁹ × 5 × 10⁻⁶ × 2.5 × 10⁻⁶ / 0.5²
F = 450 × 10⁻³
F₁ = 0.45 N (+)
Now we will find Force due to q2
F = 9 × 10⁹ × 5 × 10⁻⁶ × 2.5 × 10⁻⁶ / 0.25²
F = 1800 × 10⁻³
F₂ = 1.8 N (-)
So net force (F) will be
F = F₂ - F₁
F = 1.8 - 0.45
F = 1.35 N
Hence the net force on q2 will be 1.35 N
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Answer:31.62 m/s
Explanation:
Given
mass of body 
Pull on chain is 
Pull get smaller at the rate of 
Net Upward Force 
net acceleration 



but g is acting downward

using 
here initial velocity is zero


The jogger's average speed 1.03 m/s
<h3>
The Speed and the Velocity of a Particle in a Circle</h3>
The speed of a particle is a circle will always be constant while the velocity will not. That is, velocity varies.
Given that a jogger jogs around a circular track with a diameter of 275 m in 14.0 minutes. First convert the minutes to seconds
Given parameters are;
- Time t = 14 minutes = 14 x 60s = 840 s
Speed V = 2πr ÷ t
V = ( 2 × π × 137.5 ) ÷ 840
V = 863.9 / 840
V = 1.028 m/s
Therefore, the jogger's average speed 1.03 m/s approximately
Learn more about Circular Motion here: brainly.com/question/20905151
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