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3 years ago

a runner covers the last straigjt stretch of a race in 4 s. during that time, he speeds up from 5m/s to 9m/s.

1 answer:

8 0

During that final period of time,
his acceleration is
(9 m/s - 5 m/s) / (4 sec) = 1 m/s² .

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A 2.5 kg steel gasoline tank can holds 20.0 L of gasoline when full. What is the average density (in Kg/m^3) of the full gas can

yarga [219]

Answer:

$D=792.3\ kg/m^3$

Explanation:

<u>Average Density </u>

The density of an object of mass m and volume V is

$\displaystyle D=\frac{m}{V}$

If we know the density and the volume occupied by the object, the mass can be computed as

$m=D.V$

The tank can hold 20 L of gasoline when full. Converting to cubic meters

$V_g=20*0.001=0.02\ m^3$

That's the volume of the gasoline it contains. Knowing the density of the gasoline, we get the mass of gasoline.

$m_g=680*0.02=13.6\ kg$

To know the total mass of both, we add the 2.5 kg of the tank

$m=m_t+m_g=13.6+2.5=16.1\ kg$

The volume of the tank is computed solving for V

$\displaystyle V=\frac{m}{D}$

$\displaystyle V_t=\frac{2.5}{7800}=3.205\times 10^{-4}\ m^3$

The total volume is

$V=V_g+V_t=0.02+3.205\times 10^{-4}=0.0203\ m^3$

The average density is

$\displaystyle D=\frac{16.1}{0.0203}$

$\boxed{D=792.3\ kg/m^3}$

7 0

3 years ago

Awdfwkjbfgkjsenfkjnsekjfgnesklnslkenges

forsale [732]

Answer:

yes

Explanation:

3 0

3 years ago

Read 2 more answers

The mass of a string is 7.7 × 10-3 kg, and it is stretched so that the tension in it is 190 N. A transverse wave traveling on th

Scilla [17]

Length of the strings = 2.33 m

3 0

3 years ago

Acceleration is the magnitude of average velocity.

lina2011 [118]

Answer:

false

Explanation:

just did the question on apex, true was wrong

4 0

4 years ago

A plastic box has an initial volume of 2.00 m 3 . It is then submerged below the surface of a liquid and its volume decreases to

nikitadnepr [17]

Answer:

Volume strain is 0.02

Explanation:

Volume strain is defined as the change in volume to the original volume.

It is given that,

Initial volume of the plastic box is 2 m³

It is then submerged below the surface of a liquid and its volume decreases to 1.96 m³

We need to find the volume strain on the box. It is defined as the change in volume divided by the original volume. So,

$\delta V=\dfrac{V_f-V_i}{V_i}\\\\\delta V=\dfrac{1.96-2}{2}\\\\\delta V=0.02$

So, the volume strain on the box is 0.02.

6 0

3 years ago