How to do projects on newton’s law

A small, 300 g cart is moving at 1.20 m/s on an air track when it collides with a larger, 2.00 kg cart at rest?

stiv31 [10]

Answer:

The speed of the large cart after collision is 0.301 m/s.

Explanation:

Given that,

Mass of the cart, $m_1 = 300\ g = 0.3\ kg$

Initial speed of the cart, $u_1=1.2\ m/s$

Mass of the larger cart, $m_2 = 2\ kg$

Initial speed of the larger cart, $u_2=0$

After the collision,

Final speed of the smaller cart, $v_1=-0.81\ m/s$ (as its recolis)

To find,

The speed of the large cart after collision.

Solution,

Let $v_2$ is the speed of the large cart after collision. It can be calculated using conservation of momentum as :

$m_1u_1+m_2u_2=m_1v_1+m_2v_2$

$m_1u_1+m_2u_2-m_1v_1=m_2v_2$

$v_2=\dfrac{m_1u_1+m_2u_2-m_1v_1}{m_2}$

$v_2=\dfrac{0.3\times 1.2+0-0.3\times (-0.81)}{2}$

$v_2=0.301\ m/s$

So, the speed of the large cart after collision is 0.301 m/s.

4 0

2 years ago

Mars has two moons. What does the orbital speed of these moons depend on?

Radda [10]

Answer:

their masses and their distances from Mars

Explanation:

Hope this helped

Also can u pls mark me brainliest

8 0

3 years ago

Which answer is a scientifically accurate description of velocity?

viktelen [127]

The boat traveled from the dock north to the 200-meter marker in the bay in less than 5 minutes, giving the passengers several more hours to fish.

Explanation:

Velocity is a physical quantity that describes the rate of change of displacement with time.

Velocity = $\frac{Displacement}{time taken}$

The quantity differs from speed in that it has both magnitude and direction.

From the options given above:

Displacement: The boat traveled in the north direction from the dock to a 200m mark.

Time taken: approximately less than 5 minutes was the duration of traveling.

This describes the boat's velocity accurately.

Learn more:

Velocity brainly.com/question/10962624

#learnwithBrainly

3 0

3 years ago

Por favor ayuda que ejercicio debo hacer para enflacar en una semana xd

Serggg [28]

Answer:

Un excelente ejercicio para perder barriga rápidamente es correr, ya que el cuerpo gasta una mayor cantidad de calorías en un corto período de tiempo, en tan sólo 30 minutos corriendo se queman unas 300 calorías.

...

Qué ejercicios realizar

Correr. ...

Clase aeróbica. ...

Saltar cuerda. ...

Bicicleta. ...

Caminar rápido. ...

Natación.

Explanation:

dame coronita por favor

8 0

2 years ago

An electron that has a velocity with x component 2.6 × 106 m/s and y component 3.2 × 106 m/s moves through a uniform magnetic fi

elena55 [62]

Answer:

a) $\vec F_{B} = 8.766\times 10^{-14}\,T\,k$ , b) $\vec F_{B} = -8.766\times 10^{-14}\,T\,k$

Explanation:

a) The magnetic force experimented by a particle has the following vectorial form:

$\vec F_{B} = q\cdot \vec v \times \vec B$

The charge of the electron is equal to $-1.602\times 10^{-19}\,C$ . Then, cross product can be solved by using determinants:

$\vec F_{B} = \begin{vmatrix}i&j&k\\-4.165\times 10^{-13}\, C\cdot \frac{m}{s} &-5.126\times 10^{-13}\,C\cdot \frac{m}{s} &0\,C\cdot \frac{m}{s} \\0.041\,T&-0.16\,T&0\,T\end{vmatrix}$

The magnetic force is:

$\vec F_{B} = 8.766\times 10^{-14}\,T\,k$

b) The charge of the proton is equal to $1.602\times 10^{-19}\,C$ . Then, cross product has the following determinant:

$\vec F_{B} = \begin{vmatrix}i&j&k\\4.165\times 10^{-13}\, C\cdot \frac{m}{s} &5.126\times 10^{-13}\,C\cdot \frac{m}{s} &0\,C\cdot \frac{m}{s} \\0.041\,T&-0.16\,T&0\,T\end{vmatrix}$

The magnetic force is:

$\vec F_{B} = -8.766\times 10^{-14}\,T\,k$

8 0

2 years ago