Answer:
i don't know nothing about that
9514 1404 393
Answer:
5 1/16 ft
Step-by-step explanation:
h(t) = -16t(t -18/16) . . . . put in intercept form
The function describes a parabola that opens downward. It has zeros at t=0 and t=9/8. The maximum height will be found at the vertex of the parabola, halfway between these zeros.
f(9/16) = (-16)(9/16)² +18(9/16) = 81/16 = 5 1/16 . . . . feet
The approximate maximum height of the leopard is 5 1/16 feet.
Answer:
7/8 > 5/6
Step-by-step explanation:
A) 7/8
We can compare this as follows.
Lets say both are equal.
Cross multiplying these we get 40=42
We get 40<42. In fraction we get
In case if you want to convert this to decimal, we get;
5/6 = 0.833 and 7/8 = 0.875
We get 5/6<7/8
B) 4/5
Similarly we get 4/5 = 0.8 and 5/6 = 0.833
Here 4/5<5/6
C) 3/4
we get 3/4 = 0.75 and 5/6 = 0.833
3/4<5/6
D) 2/3
we get 2/3 = 0.66 and 5/6 = 0.833
2/3<5/6
Step-by-step explanation:
I think it would be 3569 , i’m not sure tho.
Answer:
Neighborhood Q appears to have a bigger family size
Step-by-step explanation:
Mean = the sum of all data values divided by the total number of data values
Number of families in Neighborhood Q = 9
Mean family size of Neighborhood Q:
= (2 + 5 + 4 + 3 + 2 + 5 + 3 + 6 + 5) ÷ 9
= 35 ÷ 9
= 3.888888...
Number of families in Neighborhood S = 9
Mean family size of Neighborhood S:
= (2 + 3 + 2 + 3 + 7 + 2 + 3 + 3 + 2) ÷ 9
= 27 ÷ 9
= 3
The mean family size of Neighborhood Q is 3.88.. and the mean family size of Neighborhood S is 3. Therefore, Neighborhood Q appears to have a bigger family size as it's average family size is bigger than that of Neighborhood S.
