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blagie [28]
3 years ago
7

The minimum number of triangles needed to construct the polygon Sophia made is 3. Which could show Sophia’s polygon?

Mathematics
2 answers:
schepotkina [342]3 years ago
6 0

I think the answer is 6 or 9  Because the minimum is 3 I hope this helps.

andrew11 [14]3 years ago
6 0

Answer:

6 ( OPTION B){€••€}

~

Step-by-step explanation:

3 is the minimum and half of 6 is 3✌.

If I can comment

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A 4-inch long ribbon is cut into pieces. If the length of each piece is 12of an inch, how many pieces are cut?
vekshin1

Answer:

48 pieces are cut.

Step-by-step explanation:

1/12 of an inch means that one inch would be 12 pieces. Since there are 4 pieces it would be 12x4= 48 pieces.

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What’s the quotient of 20 and 2
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the answer is 10 hoped this helped have a great day


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measure of angle ABC is 6 degree.

Step-by-step explanation:

After you found x, you'll plug it in the equation of the angle it's asking for.

Measure of angle ABD, and you know measure of angle ABC = 4x-1.

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Find the common difference of the sequence shown.
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A vessel without a lid has the shape of a cylinder. The height of the vessel is 1.5 m, and the diameter of the base represents 4
salantis [7]

Answer:

Yes, 1 kg of paint is enough to completely paint the inside and outside surfaces of the vessel.

Step-by-step explanation:

For the given vessel without a lid,

diameter = 0.4 x 1.5

               = 0.6 m

radius = \frac{diameter}{2} = \frac{0.6}{2}

           = 0.3 m

Total external surface area of the vessel = 2\pirh + \pir^{2}

                             = [2 x \frac{22}{7} x 0.3 x 1.5] + [\frac{22}{7} x (0.3)^{2}]

                             = 2.8286 + 0.2829

                             = 3.1112

Total external surface area of the vessel is 3.1112 square meter.

Total internal and external surface area = 2 x 3.1112

                                                              = 6.2224 m^{2}

But for 1 square meter, 150 g of paint is consumed. Thus;

for 6.2224 m^{2} = 6.2224 x 150 g

                       = 933.36 g

Thus, 6.2224 m^{2} of area would require 933.36 g of paint.

So that,

\frac{933.36}{1000} = 0.93336 kg

Therefore, 1 kg of paint is enough to completely paint the inside and outside surfaces of the vessel.

7 0
3 years ago
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