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blagie [28]
3 years ago
7

The minimum number of triangles needed to construct the polygon Sophia made is 3. Which could show Sophia’s polygon?

Mathematics
2 answers:
schepotkina [342]3 years ago
6 0

I think the answer is 6 or 9  Because the minimum is 3 I hope this helps.

andrew11 [14]3 years ago
6 0

Answer:

6 ( OPTION B){€••€}

~

Step-by-step explanation:

3 is the minimum and half of 6 is 3✌.

If I can comment

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A padlock has a four-digit code that includes digits from 0 to 9, inclusive. What is the probability that the code does not cons
Eduardwww [97]
Since there is no repetition allowed, there are 10 possibilities for the 1st digit, 9 for the 2nd, 8 for the 3rd, and 7 for the 4th. This gives a total of (10)(9)(8)(7) = 5040 four-digit codes.
For all odd digits to be used, there are 5 possibilities for the 1st digit (1,3,5,7,9), 4 for the 2nd, 3 for the 3rd, 2 for the 4th. This gives a total of (5)(4)(3)(2) = 120 codes that only use odd digits.
Therefore there are 5040 - 120 = 4920 codes that do not consist of all odd digits. The probability is 4920/5040 = 41/42.

4 0
2 years ago
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Through (2,-4), parallel to x=4
mote1985 [20]

Answer:

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4 0
3 years ago
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Determine whether the three segment lengths will produce a triangle. Type yes or no in the space provided.
tresset_1 [31]

Answer:

20 , 20 , 30 will produce a triangle

Step-by-step explanation:

* Lets study how to know if the lengths of the three segments

 can formed a triangle

- It is a fact that in any triangle the sum of the smallest two sides

 must be greater than the largest side

- Lets study some examples

# If the lengths of the three segments are 5 , 6 , 7

∵ 5 and 6 are the smallest

∴ 5 + 6 = 11

∵ 11 > 7 ⇒ the sum greater than the 3rd side

∴ 5 , 6 , 7 can formed a triangle

# If the lengths of the three segments are 5 , 7 , 12

∵ 5 and 7 are the smallest

∴ 5 + 7 = 12

∵ 12 = 12 ⇒ the sum equal the 3rd side

∴ 5 , 7 , 12 can not formed a triangle

# If the lengths of the three segments are 10 , 12 , 24

∵ 10 and 12 are the smallest

∴ 10 + 12 = 22

∵ 22 < 24 ⇒ the sum less than the 3rd side

∴ 10 , 12 , 24 can not formed a triangle

* Now lets solve the problem

∵ The length of the three segments are 20 , 20 , 30

∵ 20 and 20 are the smallest

∴ 20 + 20 = 40

∵ 40 > 30 ⇒ the sum greater than the 3rd side

∴ 20 , 20 , 30 will produce a triangle

5 0
2 years ago
A rectangle has vertices (w,v), (w,z), and (z,z). Find the fourth vertex.
exis [7]

9514 1404 393

Answer:

  (z, v)

Step-by-step explanation:

When the sides of the rectangle align with the axes, as here, the coordinates will be all (x, y) combinations from the sets x ∈ {w, z) and y ∈ {v, z}. Three of those combinations are shown. The fourth is (z, v).

5 0
2 years ago
I need help plz and I have to show work
bija089 [108]

This is a very simple and easy problem. I'm not sure why you need someone else to solve it, but I hope this helps

a. Linear equation:

Let x be amount of movies rented

$8 + ($2.50 * x)

b.

$8 + ($2.50 * 10)

= $8 + $25.0

= $33

8 0
2 years ago
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