Answer: -
IE 1 for X = 801
Here X is told to be in the third period.
So n = 3 for X.
For 1st ionization energy the expression is
IE1 = 13.6 x Z ^2 / n^2
Where Z =atomic number.
Thus Z =( n^2 x IE 1 / 13.6)^(1/2)
Z = ( 3^2 x 801 / 13.6 )^ (1/2)
= 23
Number of electrons = Z = 23
Nearest noble gas = Argon
Argon atomic number = 18
Number of extra electrons = 23 – 18 = 5
a) Electronic Configuration= [Ar] 3d34s2
We know that more the value of atomic radii, lower the force of attraction on the electrons by the nucleus and thus lower the first ionization energy.
So more the first ionization energy, less is the atomic radius.
X has more IE1 than Y.
b) So the atomic radius of X is lesser than that of Y.
c) After the first ionization, the atom is no longer electrically neutral. There is an extra proton in the atom.
Due to this the remaining electrons are more strongly pulled inside than before ionization. Hence after ionization, the radii of Y decreases.
An oxidation number is the electrical charge a molecule or ion appears to have as determined by a set of arbitary rules.
Answer:
Tollen's test or silver mirror test is use to distinguish between ketone and aldehyde.
Explanation:
Tollen's test is use to distinguish aldehyde from ketone because Tollen reagent consist of silver nitrate and ammonia and it oxidized aldehydes to carboxylic acid and the silver Ag+ is reduced to solid silver Ag. It form a inner film wall on the tube that look like mirror. Ketone do not react with Tollen reagent and therefore does not form silver mirror on the tube wall.
Answer:
see explanation
Explanation:
The Lewis structure of a substance is otherwise known as its dot electron structure. It gives an immediate picture of the bonding and number of electron pairs in the molecule. The diagram shows only the valence electrons on each of the bonding atoms in the molecule and how they combine to form the molecule under consideration.
The correct Lewis structure for CO2 is shown in the image attached. CO2 has 16 valence electrons. This can be verified by counting the number of dots in the image attached.
Answer:
2.0 M
Explanation:
Step 1: Given data
- Mass of NaCl (solute): 2.93 g
- Volume of the solution: 0.025 L
Step 2: Calculate the moles corresponding to 2.93 g of NaCl
The molar mass of NaCl is 58.44 g/mol.
2.93 g × 1 mol/58.44 g = 0.0501 mol
Step 3: Calculate the molarity of the solution
Molarity is equal to the moles of solute divided by the liters of solution.
M = 0.0501 mol/0.025 L = 2.0 M
