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Leona [35]
2 years ago
6

The half-life of a radioactive isotope is 20 minutes. What is the total amount of 1.00 g of sample of this isotope remaining aft

er 1 hour?
Chemistry
1 answer:
Nikolay [14]2 years ago
6 0
So since every 20 mins the mass will be cut in half (and that happens 3 times), you have just got to divide 1g by 2, 3 times.

after 20 mins the mass will be .5

after 40 mins the mass will be .25

Answer: After 1 hour the mass will be .125g
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pashok25 [27]

Answer:

moles Ar in 20g = 0.500 mole Ar

Explanation:

moles = grams given / formula weight = 20g / 39.948g·mol⁻¹ = 0.500 mole Ar

7 0
2 years ago
Indicate the correct number of sig figs
Dimas [21]

Explanation:

The answer to questions are

A) 4

B) 3

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D) 3

E) 3

3 0
2 years ago
Copper has two naturally occurring isotopes. Cu−63 has a mass of 62.939 amu and relative abundance of 69.17%.
fiasKO [112]
The answer is 64.907 amu.

The atomic mass of an element is the average of the atomic masses of its isotopes. The relative abundance of isotopes must be taken into consideration, therefore:
atomic mass of copper = atomic mass of isotope 1 * abundance 1 + atomic mass of isotope 2 * abundance 2

We know:
atomic mass of copper = 63.546 amu
The atomic mass of isotope 1 is: 62.939 amu
The abundance of isotope 1 is: 69.17% = 0.6917
The atomic mass of isotope 1 is: x
The abundance of isotope 2: 100% - 69.17% = 30.83% = 0.3083

Thus:
63.546 amu = 62.939 amu * 0.6917 + x * 0.3083
63.546 <span>amu = 43.535 amu + 0.3083x
</span>⇒ 63.546 amu - 43.535 amu = 0.3083x
⇒ 20.011 amu = 0.3083x
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7 0
3 years ago
What is the usual charge on an ion from group 7a
alexdok [17]
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4 0
3 years ago
Calculate the amount of grams of water that was used when 5525J of energy was used to boil this amount of water.
djverab [1.8K]

Answer:

2.445 g

Explanation:

Step 1: Given and required data

  • Energy in the form of heat required to boil the water (Q): 5525 J
  • Latent heat of vaporization of water (∆H°vap): 2260 J/g
  • Mass of water (m): ?

Step 2: Calculate the mass of water

We will use the following expression.

Q = ∆H°vap × m

m = Q / ∆H°vap

m = 5525 J / (2260 J/g)

m = 2.445 g

4 0
2 years ago
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