Solution:
we are given that
Clayton needs to reflect the triangle below across the line y=x.
And as we know the reflection of the point (x,y) across the line y = x is the point (y, x).
Hence the new Traingle will be on the other side of the line y=x and position of x and y-coordinates of the vertices of the trangle gets interchanged.
Hence the Options that applies are:
C’ will move because all points move in a reflection.
The image and the pre-image will be congruent triangles. (Because reflection just changes the position of the trinagle not the property)
The image and pre-image will not have the same orientation because reflections flip figures.
Answer:
0.045
Hope this helpful! Have a great night/day!
Answer:
m=-3
c=1
Step-by-step explanation:
y=mx+c
m is -3 which is the coefficient of x and c is the intercept 1
Answer:
Ray 23
Step-by-step explanation:
Answer:
Step-by-step explanation:
coordinate of O(2,1),Y(3,-2),T(-3,-3)
let the reflected points are O',Y',T'
distance of O from y=2 is 1 unit.
∴ ordinate of O' =1+2(1)=3
or O' is (2,3)
distance of Y from y=2 is2+2=4
ordinate of Y'=-2+2(4)=6
so coordinate of Y' is (3,6)
distance of T from y=2 is (2+3)=5
so ordinate of T' =-3+2(5)=7
coordinate of T' is(-3,7)