Question

What is the abscissa of the midpoint of the line segment whose endpoints are (5, 2) and (2, 2)?

Answer 1

Answer:

Midpoint is (3.5, 2)

Step-by-step explanation:

the midpoint of the line segment whose endpoints are (5, 2) and (2, 2)

To find midpoint of two end points we use formula

$(\frac{x_1+x_2}{2} , \frac{y_1+y_2}{2})$

(5, 2) , x1 = 5  and y1= 2

(2,2), x2=2  and y2= 2

Plug in all the values and find the midpoint using the formula

$(\frac{5+2}{2},\frac{2+2}{2})$

$(\frac{7}{2},\frac{4}{2})$

(3.5, 2)

So midpoint is (3.5,2)

Answer 2

Answer:

The abscissa of obtained mid point is 3.5

Step-by-step explanation:

We are given the following information in the question:

Endpoints of a line segment are (5, 2) and (2, 2).

Mid point formula:

$(x,y) = \bigg(\displaystyle\frac{x_1+x_2}{2}, \displaystyle\frac{y_1+y_2}{2}\bigg)$

where (x,y) is the mid point and $(x_1,y_1),(x_2.y_2)$ are the ends of line segment.

Putting the values:

$(x,y) = \bigg(\displaystyle\frac{5+2}{2}, \displaystyle\frac{2+2}{2}\bigg) = (3.5,2)$

The abscissa is the x coordinate of the point.

The abscissa of obtained mid point is 3.5