Answer:
a) The formal charge on N is 0 in both species.
Explanation:
The formal charge is calculated using the formular;
FC = V-N-B/2
Where;
V = Number of Valence electrons
N = number of nonbonding valence electrons
B = total number of electrons shared in bonds
In NO2-;
The formal charge of N is given as;
FC = 5 - 2 - 6/2
FC = 0
In HNO2
The formal charge of N is given as;
FC = 0
The correct option is;
a) The formal charge on N is 0 in both species.
Answer:
You can better relate to the air temperature.
Explanation:
Fahrenheit gives you almost double the precision of Celsius without having to use decimals.
The density of the metal with a mass of 1.71g that was dropped into a graduated cylinder containing 17.00 mL of water is 1.005g/mL.
<h3>How to calculate density?</h3>
The density of a substance can be calculated by dividing the mass of the substance by its volume. That is;
Density = mass ÷ volume
According to this question, a piece of metal with a mass of 17.1 g was dropped into a graduated cylinder containing 17.00 mL of water. The density can be calculated as follows:
Density = 17.1g ÷ 17.00mL
Density = 1.005g/mL
Therefore, the density of the metal with a mass of 1.71g that was dropped into a graduated cylinder containing 17.00 mL of water is 1.005g/mL.
Learn more about density at: brainly.com/question/15164682
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Answer: 1. Mass and type of solution
2. Type of material
3. Temperature
Answer: Option (2) is the correct answer.
Explanation:
Atomic number of oxygen atom is 8 and its electronic distribution is 2, 6. So, it contains only 2 orbitals which are closer to the nucleus of the atom.
As a result, the valence electrons are pulled closer by the nucleus of oxygen atom due to which there occurs a decrease in atomic size of the atom.
Whereas atomic number of sulfur is 16 and its electronic distribution is 2, 8, 6. As there are more number of orbitals present in a sulfur atom so, the valence electrons are away from the nucleus of the atom.
Hence, there is less force of attraction between nucleus of sulfur atom and its valence electrons due to which size of sulfur atom is larger than the size of oxygen atom.
Thus, we can conclude that the oxygen atom is smaller than the sulfur atom because the outer orbitals of oxygen are located closer to the nucleus than those of sulfur.
