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Arlecino [84]
3 years ago
15

generally speaking electrons are found in shells which we also call principal energy levels located at increasing distances from

the central nucleus the first ionization energy or ie with little sub 1 of an atom of an element describes the amount of energy required to remove the outermost electron from an atom of a_____________________.
Chemistry
1 answer:
xeze [42]3 years ago
7 0

Answer:

Gas

Explanation:

Ionization energy is the energy required to remove the most loosely held electron from a gaseous atom or ion. For the first Ionization energy, it is the energy needed to remove the most loosely bound electron from a gaseous atom

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If 125 grams of Cu reacts 75 grams of HNO3, how many grams of Cu(NO3) form?
melisa1 [442]

Answer: 37.5grams of Cu(NO3)2

Cu(1mol) + 2HNO3(2mol) —> Cu(NO3)2 + H2

<em>125 grams of Cu(1mol) reacts with 75 grams of HNO3(2mol)</em>

<em><u>HNO3 is the limiting substance, therefore, 75 grams is the limiting quantity.</u></em>

<em>Therefore, 2mol of HNO3 forms 1mol of Cu(NO3)2</em>

<em>75 grams of HNO3 forms...75grams x 1mol/2mol = 37.5 grams of Cu(NO3)2</em>

3 0
2 years ago
Calculate the average bond order for a p−o bond (such as the one shown in blue) in a phosphate ion. express your answer numerica
PtichkaEL [24]
<span>Answer: 1/4 is the average bond order for a pâ’o bond (such as the one shown in blue) in a phosphate ion.</span>
5 0
3 years ago
Show
SIZIF [17.4K]

Answer: 0.9375 g

Explanation:

To calculate the number of moles for given molarity, we use the equation:

\text{Moles of solute}={\text{Molarity of the solution}}\times{\text{Volume of solution (in L)}}     .....(1)

Molarity of HCl solution = 0.75 M

Volume of HCl solution = 25.0 mL = 0.025 L

Putting values in equation 1, we get:

\text{Moles of} HCl={0.75}\times{0.025}=0.01875moles  

CaCO_3(s)+2HCl(aq)\rightarrow CaCl_2(s)+CO_2(g)+H_2O(l)  

According to stoichiometry :

2 moles of HCl require = 1 mole of CaCO_3

Thus 0.01875 moles of HCl will require=\frac{1}{2}\times 0.01875=0.009375moles  of CaCO_3

Mass of CaCO_3=moles\times {\text {Molar mass}}=0.009375moles\times 100g/mol=0.9375g

Thus 0.9375 g of CaCO_3 is required to react with 25.0 ml of 0.75 M HCl

6 0
2 years ago
Aqueous sodium phosphate and aqueous iron (III) chloride react to produce aqueous sodium chloride and solid iron (III) phosphate
mojhsa [17]

Answer:

this one is hard

Explanation:

but it's iron because the sodium so yea there u go.

4 0
2 years ago
Which elements are present in the compound aluminium nitrate?
PSYCHO15rus [73]

Answer:

Aluminum nitrate is a salt composed of aluminum and nitric acid, belonging to a group of reactive chemicals - organic nitrate and nitrite compounds. The nitrate ion is polyatomic, meaning it is composed of two or more ions that are covalently bonded. This ion makes up the conjugate base of nitric acid.

Explanation:

4 0
2 years ago
Read 2 more answers
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