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Arlecino [84]
4 years ago
15

generally speaking electrons are found in shells which we also call principal energy levels located at increasing distances from

the central nucleus the first ionization energy or ie with little sub 1 of an atom of an element describes the amount of energy required to remove the outermost electron from an atom of a_____________________.
Chemistry
1 answer:
xeze [42]4 years ago
7 0

Answer:

Gas

Explanation:

Ionization energy is the energy required to remove the most loosely held electron from a gaseous atom or ion. For the first Ionization energy, it is the energy needed to remove the most loosely bound electron from a gaseous atom

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At STP, which sample contains the same number of molecules as 11.2 liters of CO2(g) at STP?
Lana71 [14]
The answer is (3) 11.2 L of N2(g). When the choices are all gases, the number of molecules depends on the molar number of the gas. Under the condition of STP, the molar number of a gas is depends on volume only. So the same volume of gas has the same number of molecules.
8 0
4 years ago
Why isn’t there a lunar eclipse every time Earth is in between the sun and the Moon?
QveST [7]

Answer: Exploratorium Senior Scientist Paul Doherty explains why not—the orbit of the moon is tilted relative to the orbit of the Earth around the sun, so the moon often passes below or above Earth. At those times, it does not cross the line between the sun and the Earth, and therefore does not create a solar eclipse.

HOPE THIS HELPS

8 0
3 years ago
Using the balanced equation below, how many grams of cesium fluoride would be required to make 73.1 g of cesium xenon heptafluor
jenyasd209 [6]

Answer:

27.9 g

Explanation:

CsF + XeF₆ → CsXeF₇

First we <u>convert 73.1 g of cesium xenon heptafluoride (CsXeF₇) into moles</u>, using its<em> molar mass</em>:

  • Molar mass of CsXeF₇ = 397.193 g/mol
  • 73.1 g CsXeF₇ ÷ 397.193 g/mol = 0.184 mol CsXeF₇

As <em>1 mol of cesium fluoride (CsF) produces 1 mol of CsXeF₇</em>, in order to produce 0.184 moles of CsXeF₇ we would need 0.184 moles of CsF.

Now we <u>convert 0.184 moles of CsF to moles</u>, using the <em>molar mass of CsF</em>:

  • Molar mass of CsF = 151.9 g/mol
  • 0.184 mol * 151.9 g/mol = 27.9 g
4 0
3 years ago
Two samples of the same compound are compared. what does the data represent? sample 1: 24.22 g carbon and 32.00 g oxygen sample
goblinko [34]

According to law of definite proportion:

In a compound, elements are always arranged in fixed ratio by mass.

Here, sample 1 has 23.22 g Carbon and 32.00 g Oxygen.

Converting mass into number of moles:

Molar mass of carbon is 12 g/mol and that of oxygen is 16 g/mol thus,

n_{C}=\frac{m_{C}}{M_{C}}=\frac{24.22 g}{12 g/mol}\approx 2 mol

Similarly, number of moles of oxygen will be:

n_{O}=\frac{m_{O}}{M_{O}}=\frac{32 g}{16 g/mol}=2 mol

The ratio of number of moles of carbon and oxygen will be:

C:O=n_{C}:n_{O}=2:2=1:1

Therefore, formula of compound will be CO.

Sample 2:

It has 36.22 g Carbon and 48.00 g Oxygen.

Converting mass into number of moles:

Molar mass of carbon is 12 g/mol and that of oxygen is 16 g/mol thus,

n_{C}=\frac{m_{C}}{M_{C}}=\frac{36.22 g}{12 g/mol}\approx 3 mol

Similarly, number of moles of oxygen will be:

n_{O}=\frac{m_{O}}{M_{O}}=\frac{48 g}{16 g/mol}=3 mol

The ratio of number of moles of carbon and oxygen will be:

C:O=n_{C}:n_{O}=3:3=1:1

The formula of compound will be CO.

Therefore, it is proved that carbon and oxygen are present in fixed ratios in both the samples.


4 0
3 years ago
How many liters are there in 144g of H₂O (g)?<br> What is the mass of 200L at STP of H₂O₂ (g)?
Lisa [10]

Answer:

1. 179.2 L

2. 303.62 g

Explanation:

1. Determination of volume of H₂O (g).

We'll begin by calculating the number of mole in 144 g of H₂O. This is illustrated below:

Mass of H₂O = 144 g

Molar mass of H₂O = (2×1) + 16 = 2 + 16 = 18 g/mol

Mole of H₂O =?

Mole = mass /Molar mass

Mole of H₂O = 144/18

Mole of H₂O = 8 moles

Finally, we shall determine volume of H₂O (g) as follow:

1 mole of any gas occupy 22.4L at stp.

Therefore, 8 moles of H₂O (g) will occupy =

8 × 22.4 = 179.2 L

Thus, 144 g of H₂O (g) occupies 179.2 L

2. Determination of the mass of H₂O₂ (g).

We'll begin by calculating the number of mole of H₂O₂ (g) that occupied 200 L at STP. this can be obtained as follow:

1 mole of any gas occupy 22.4 L at stp.

Therefore, Xmol of H₂O₂ (g) will occupy 200 L at STP i.e

Xmol of H₂O₂ (g) = 200/22.4

Xmol of H₂O₂ (g) = 8.93 moles

Thus, 8.93 moles of H₂O₂ (g) occupied 200 L at STP.

Finally, we shall determine the mass of H₂O₂ (g) as follow:

Mole of H₂O₂ (g) = 8.93 moles

Molar mass of H₂O₂ = (2×1) + (2×16) = 2 + 32 = 34 g/mol

Mass of H₂O₂ =?

Mole = mass /Molar mass

8.93 = mass of H₂O₂ /34

Cross multiply

Mass of H₂O₂ = 8.93 × 34

Mass of H₂O₂ = 303.62 g

5 0
3 years ago
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