Answer:
Whether the forces of attraction is strong or weak is explained below in details.
Explanation:
There are three distinct kinds of intermolecular forces in expressions of energy. They are (strongest to weakest) dipole-dipole, hydrogen bonding, and Van der Waals' strengths. Intermolecular forces are weak related to intramolecular forces – the energies which endure a molecule collectively. For instance, the covalent bond, including distributing electron sets among atoms, is much more powerful than the forces impersonate among neighboring molecules.
2 NI₃= N₂ + 3 I₂
2 x 394.71 g --------------- 3 x 253.80 g
3.58 g ---------------------- ( mass of I₂ )
3.58 x 3 x 253.80 / 2 x 394.71 =
2725.812 / 789.42 => 3.4529 g of I₂
1 mole I₂ --------------- 253.80 g
?? ----------------------- 3.4529 g
3.4529 x 1 / 253.80 => 0.0136 moles of I₂
Answer C
hope this helps!
There is a thing called gravity. Gravity in the earth causes anything to stay down. There was an experiment a person held a plastic box with bricks on earth. It was really hard to pick it up. Then in the ISS (International Space Station) the same person help and it was so much easier no hardship at all, even a baby can do it!!
5. Length times With times Hight = Volume or L*W*H=V
Answer: 4.05 mol O2, 15.36 mol H2O
Explanation:
I can answer each question individually if you post them individually.
2a. 3.24 mol NH3 * (5 mol O2 / 4 mol NH3) = 4.05 mol O2
2b. 12.8 mol O2 ( 6mol H2O/ 5 mol O2) = 15.36 mol H2O
Essentially what I did was dimensional analysis. Multiplying in a way that the units cancel out so the only thing remains is what each question asks for.
Answer:
the stronger light 5.5 m apart from the total illumination
Explanation:
From the problem's statement , the following equation can be deducted:
I= k/r²
where I = intensity of illumination , r= distance between the point and the light source , k = constant of proportionality
denoting 1 as the stronger light and 2 as the weaker light
I₁= k/r₁²
I₂= k/r₂²
dividing both equations
I₂/I₁ = r₁²/r₂²=(r₁/r₂)²
solving for r₁
r₁ = r₂ * √(I₂/I₁)
since we are on the line between the two light sources , the distance from the light source to the weaker light is he distance from the light source to the stronger light + distance between the lights . Thus
r₂ = r₁ + d
then
r₁ = (r₁ + d)* √(I₂/I₁)
r₁ = r₁*√(I₂/I₁) + d*√(I₂/I₁)
r₁*(1-√(I₂/I₁)) = d*√(I₂/I₁)
r₁ = d*√(I₂/I₁)/(1-√(I₂/I₁)) =
r₁ = d/[√(I₁/I₂)-1)]
since the stronger light is 9 times more intense than the weaker
I₁= 9*I₂ → I₁/I₂ = 9 →√(I₁/I₂)= 3
then since d=11 m
r₁ = d/[√(I₁/I₂)-1)] = 11 m / (3-1) = 5.5 m
r₁ = 5.5 m
therefore the stronger light 5.5 m apart from the total illumination
