1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
soldi70 [24.7K]
3 years ago
7

The oxygen atom is smaller than the sulfur atom because _____(1) the outer electrons of oxygen are more effectively screened fro

m the nuclear charge than are sulfur’s outer electrons. (2) the outer orbitals of oxygen are located closer to the nucleus than those of sulfur. (3) the oxygen atom is larger than the sulfur atom. (4) the outer electrons of oxygen are less effectively screened from the nuclear charge than are sulfur’s outer electrons. (5) the outer orbitals of oxygen are located farther away from the nucleus than those of sulfur.
Chemistry
1 answer:
Romashka [77]3 years ago
3 0

Answer: Option (2) is the correct answer.

Explanation:

Atomic number of oxygen atom is 8 and its electronic distribution is 2, 6. So, it contains only 2 orbitals which are closer to the nucleus of the atom.

As a result, the valence electrons are pulled closer by the nucleus of oxygen atom due to which there occurs a decrease in atomic size of the atom.

Whereas atomic number of sulfur is 16 and its electronic distribution is 2, 8, 6. As there are more number of orbitals present in a sulfur atom so, the valence electrons are away from the nucleus of the atom.

Hence, there is less force of attraction between nucleus of sulfur atom and its valence electrons due to which size of sulfur atom is larger than the size of oxygen atom.

Thus, we can conclude that the oxygen atom is smaller than the sulfur atom because the outer orbitals of oxygen are located closer to the nucleus than those of sulfur.

You might be interested in
Calculate the percent activity of the radioactive isotope strontium-89 remaining after 5 half-lives.
maria [59]
The answer to this question would be: 3.125%

Half-life is the time needed for a radioactive molecule to decay half of its mass. In this case, the strontium-89 is already gone past 5 half lives. Then, the percentage of the mass left after 5 half-lives should be:
100%*(1/2^5)= 100%/32=3..125%
5 0
3 years ago
If the solubility of sodium chloride is 36 grams per 100 grams of water, which of the following solutions would be considered un
Murrr4er [49]

Answer: If the solubility of sodium chloride is 36 grams per 100 grams of water then 5.8 moles of NaCl dissolved in 1 L of water solution would be considered unsaturated.

Explanation:

A solution which contains the maximum amount of solute is called a saturated solution. Whereas a solution in which more amount of solute is able to dissolve is called an unsaturated solution.

Now, the number of moles present in 36 g of NaCl (molar mass = 58.4 g/mol) is as follows.

No. of moles = \frac{mass}{molar mass}\\= \frac{36 g}{58.4 g/mol}\\= 0.616 mol

This shows that solubility of sodium chloride is 36 grams per 100 grams of water means a maximum of 0.616 mol of NaCl will dissolve in 100 mL of water.

So, a solution in which number of moles of NaCl are less than 0.616 mol per 100 mL then the solution formed will be an unsaturated solution.

  • As 5.8 moles of NaCl dissolved in 1 L (or 1000 mL) of water. So, moles present in 100 mL are calculated as follows.

Moles = \frac{5.8 mol}{1000 mL} \times 100 mL\\= 0.58 mol

  • Moles present in 100 mL of water for 3.25 moles of NaCl dissolved in 500 ml in water are as follows.

Moles = \frac{3.25 mol}{500 mL} \times 100 mL\\0.65 mol

  • Moles present in 100 mL of water for 1.85 moles of NaCl dissolved in 300 ml of water are as follows.

Moles = \frac{1.85 mol}{300 mL} \times 100 mL\\= 0.616 mol

Thus, we can conclude that if the solubility of sodium chloride is 36 grams per 100 grams of water then 5.8 moles of NaCl dissolved in 1 L of water solution would be considered unsaturated.

8 0
3 years ago
What is the molarity of a solution containing 0.32 moles of NaCI in 3.4 liters
CaHeK987 [17]

Answer:

.094 M

Explanation: 0.32molNaCl/ 3.4L = .094M

3 0
3 years ago
What factors help veins push blood back to the heart
Vladimir79 [104]
Contractions of the skeletal muscles
As it puts pressure and moves the blood along
5 0
3 years ago
Compounds pure substances made of two or more types of _____ and are _____ _______
melomori [17]

Answer: chemical substance

Explanation:

4 0
3 years ago
Other questions:
  • From the solubility curve, which salt shows the least change in solubility as the temperature increases?
    8·1 answer
  • A mercury manometer is used to measure pressure in the container illustrated. Calculate the pressure exerted by the gas if atmos
    14·1 answer
  • The SI unit of time is the second, which is defined as 9,192,631,770 cycles of radiation associated with a certain emission proc
    14·2 answers
  • Help on question 1b please? (image attached)
    13·1 answer
  • One reaction involved in the conversion of iron ore to the metal is FeO(s) + CO(g) → Fe(s) + CO2(g) Use Hess’s Law to calculate
    15·1 answer
  • 10 point + brainlyiest= 1 big thank u
    9·2 answers
  • Volcanoes are openings in Earths crust where lava, gas, and ash can erupt. Where are active volcanoes located?
    13·2 answers
  • A flask of fixed volume contains 1.00 mole of gaseous carbon dioxide and 88.0 g of solid carbon dioxide. The original pressure a
    5·1 answer
  • g n the Ideal Gas Law lab, how is the temperature of the hydrogen gas determined? Select one: The pressure of the gas is determi
    8·1 answer
  • Can someone help me with my stoichiometry homework, it is due tonight.
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!