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3 years ago

Write the nuclear symbol for the ion with 33 protons, 42 neutrons, and 36 electrons.

Chemistry

1 answer:

mario62 [17]3 years ago

5 0

Answer:

umm I really don't know but hold on imma try

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Acids and bases can neutralize each other in double displacement reactions. For example, if hydrogen chloride (a strong acid, HC

scoray [572]

Answer:

The answer to your question is HCl + NaOH ⇒ NaCl + H₂O

Explanation:

Data

Double displacement reaction

Balanced chemical reaction

HCl + NaOH ⇒ NaCl + H₂O

Reactants Elements Products

1 Chlorine (Cl) 1

1 Sodium (Na) 1

2 Hydrogen (H) 2

1 Oxygen (0) 1

As we can see, the reaction is balanced and the coefficients of all reactants and products are 1, but the number is not written in a balanced reaction.

8 0

3 years ago

Using the periodic table, choose the more reactive metal.<br><br> Ta or V

Vera_Pavlovna [14]

V is more reactive, hope this helps!

4 0

3 years ago

Read 2 more answers

Hydrogen sulfate reacts with water to produce sulfate ions and hydronium ions: hso4−+h2o⇌so42−+h3o+ identify the conjugate acid-

Angelina_Jolie [31]

The generic equation for a reaction between an acid and water is

$HX_{(aq)} + H_{2}O_{(aq)} --> X_{(aq)}^{-} + H_{3}O_{(aq)}^+$

When an acid "reacts" with water, water acts as the base that accepts the proton (H+) from the acid. The remaining ion that is formed after the acid has donated its proton is called the conjugate base ( $X^-$ ), and the conjugate acid-base pair is $HX$ - $X^-$ .

Hydrogen sulfate ( $HSO_{4}^-$ ) is an ion from sulfuric acid. It is still an acid in itself and can "react" with water (( $H_{2}O$ ) to form the sulfate ( $SO_{4}^2-$ ) and hydronium ( $H_{3}O^+$ )ions.

$HSO_{4(aq)}^{-} + H_{2}O_{(aq)} --> SO_{4(aq)}^{2-} + H_{3}O_{(aq)}^+$

Based on the previous discussion, $SO_{4(aq)}^2-$ is identified to be the conjugate of the acid $HSO_{4(aq)}^-$ . Thus, the conjugate acid-base pair is $HSO_{4(aq)}^{-} - SO_{4(aq)}^{2-}$ .

8 0

3 years ago

If a student has 50.0 mL of a solution of 0.100 M HCI, how could they make a solution with a concentration of 0.0500 M?

vfiekz [6]

Answer:

100 ml

Explanation:

c1×v1=c2×v2

50(0.100)=0.0500(v2)

5=0.0500(v2)

5/0.0500=0.0500/0.0500(v2)

100= v2

5 0

3 years ago

7. An 8.92 kilogram bar of steel at 25°C is heated in order to shape it into a beam. The amount of heat energy

kobusy [5.1K]

Answer:

1279 °C

Explanation:

Data Given:

Amount of Heat absorb = 5.82 x 10³ KJ

Convert KJ to J

1 KJ = 1000 J

5.82 x 10³ KJ = 5.82 x 10³ x 1000 = 5.82 x10⁶ J

mass of sample = 8.92 Kg

Convert Kg to g

1 kg = 1000 g

8.92 Kg = 8.92 x 1000 = 8920 g

Cs of steel = 0.51 J/g °C

change in temperature = ?

Solution:

Formula used

Q = Cs.m.ΔT

rearrange the above equation to calculate the mass of steel sample

ΔT = Q / Cs.m .... . . . . . (1)

Where:

Q = amount of heat

Cs = specific heat of steel = 0.51 J/g °C

m = mass

ΔT = Change in temperature

Put values in above equation 1

ΔT = 5.82 x10⁶ J / 0.51 (J/g °C) x 8920 g

ΔT = 5.82 x10⁶ J /4549.2 (J/°C)

ΔT = 1279 °C

So,

change in temperature = 1279 °C

4 0

3 years ago