Answer:
So ²³⁵UF₆ effuses 1.0043 times faster than ²³⁸UF₆
Explanation:
The rate of effusion of two gases A and B can be expressed by <em>Graham's law</em>:
Where M is the molar mass, and in this case A is ²³⁵UF₆ while B is ²³⁸UF₆.
So now we <u>calculate the molar mass of each mass</u>:
²³⁵UF₆ ⇒235 + 6*19 = 349 g/mol
²³⁸UF₆ ⇒238 + 6*19 = 352 g/mol
Putting the data in Graham's law:
= 1.0043
So ²³⁵UF₆ effuses 1.0043 times faster than ²³⁸UF₆.
Answer:
3Mg + Fe₂O₃ → 3MgO + 2Fe.
Explanation:
- To balance the equation, you should apply the law of conservation of mass for the equations.
- The law of conservation of mass states that the no. of each atom is equal in both sides (reactants and products).
- The balanced equation is:
<em>3Mg + Fe₂O₃ → 3MgO + 2Fe.</em>
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That 3.0 mole of Mg react with 1.0 mole of Fe₂O₃ to produce 3.0 moles of MgO and 2.0 moles of Fe.
- The no. of all atoms is the same in both of reactants and products side.
Mg (3), Fe (2), and O (3).
Answer:
87.54 g of H₂O₂
Explanation:
From the question given above, the following data were obtained:
Number of molecules = 1.55×10²⁴ molecules
Mass of H₂O₂ =.?
From Avogadro's hypothesis,
6.02×10²³ molecules = 1 mole of H₂O₂
Next, we shall determine the mass of 1 mole of H₂O₂. This can be obtained as follow:
1 mole of H₂O₂ = (2×1) + (2×16)
= 2 + 32
= 34 g
Thus,
6.02×10²³ molecules = 34 g of H₂O₂
Finally, we shall determine mass of H₂O₂ that contains 1.55×10²⁴ molecules. This can be obtained as follow:
6.02×10²³ molecules = 34 g of H₂O₂
Therefore,
1.55×10²⁴ molecules
= (1.55×10²⁴ × 34)/6.02×10²³
1.55×10²⁴ molecules = 87.54 g of H₂O₂
Thus, 87.54 g of H₂O₂ contains 1.55×10²⁴ molecules.
Answer : The correct expression is, (150 × 3 × 31.998) ÷ (232.29 × 1) grams
Explanation :
First we have to calculate the moles of 
Now we have to calculate the moles of 
The balanced chemical reaction is,
From the balanced chemical reaction we conclude that,
As, 1 mole of react to give 3 mole of
So, 
moles of react to give 
moles of
Now we have to calculate the mass of
Therefore, the correct expression for the mass of oxygen gas formed is, (150 × 3 × 31.998) ÷ (232.29 × 1) grams
Answer: 1:3
Explanation:
1) To state the mole ratio of a product and a reactant we need the chemical equation that shows the reaction.
2) In the case of Fe3O4 and Fe, the chemical equation is:
<span> Fe+H2O → Fe3O4+H2.
3) Now, you balance the equation, which will give you the coefficients of each reactant and product of the chemical reaction:
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<span> 3Fe+4H2O → Fe3O4+4H2
4) From that the mole ratios are:
3 mol Fe : 4 mol 4H2O : 1 mol Fe3O4 : 4 mol H2.
5) The question requires you to find the mole ratio for Fe3O4 to Fe. Tha is:
1 mole Fe3O4 : 3 mole Fe
So, the answer is 1:3
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