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4 years ago

Find the acute angle θ cosθ = 0.5 (to the nearest degree)

Mathematics

1 answer:

skelet666 [1.2K]4 years ago

7 0

Cos60° = 0.5

Any angle less than 90° is an acute angle.

Therefore, 60° is the acute angle.

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A department store sells t-shirts for $16.00. Every month that a t-shirt doesn’t sell, the store reduces the selling price by 25

algol13

Answer:

Step-by-step explanation:

A = 25% of 16 = $=\frac{25}{100}*8=\frac{1}{4}*8=2$

Selling price after reduction = 16 - 2 = $14

B= 25% of 14

$=\frac{25}{100}*14=\frac{1}{4}*14=\frac{7}{2}$

= 3.5

Selling price = 14 - 3.5 = $10.5

C = 25% of 10.5

$=\frac{25}{100}*10.5=\frac{10.5}{4}$

= 2.625 = $ 2.63

Selling price = 10.5 - 2.63 = $ 7.87

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3 years ago

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Simplify the expression: 5(1 - 9a)

Marina CMI [18]

<h2>Answer:</h2><h2>5 − 45a </h2><h2>~</h2><h3>Hope you have a good day, Loves!</h3>

Also if I'm right can you let me know please?

Also Also if I am right can I please have Brainliest??

<em>You don't need to, I'm just glad I could help. ^^</em>

6 0

3 years ago

Find the percent of the area under the density curve where x is more than 3. <br>

Gekata [30.6K]

Answer:

The percent of the area under the density curve where $x$ is more that 3 is 25 %.

Step-by-step explanation:

Since the density curve is a linear function, the area under the curve can be calculated by the geometric formula for a triangle, defined by the following expression:

$A = \frac{1}{2}\cdot (x_{f} - x_{o})\cdot (y_{f}-y_{o})$ (1)

Where:

$A$ - Area, in square units.

$x_{f} - x_{o}$ - Base of the triangle, in units.

$y_{f} - y_{o}$ - Height of the triangle, in units.

The percent of the area is the ratio of triangle areas under the density curve multiplied by 100 per cent, that is:

$x = \frac{\frac{1}{2}\cdot (5-3)\cdot (0.25) }{\frac{1}{2}\cdot (5-1)\cdot (0.5) }\times 100\,\%$

$x = 25\,\%$

The percent of the area under the density curve where $x$ is more that 3 is 25 %.

7 0

3 years ago

Which of

Kryger [21]

Answer:

B 20 x 5

Step-by-step explanation:

8 0

3 years ago

A linear function contains these points: (0,-1) & (3,8)

Elenna [48]

Answer:

slope: 3

y-intercept: (0, -1)

Find slope:

$\sf slope : \dfrac{y_2 - y_1}{x_2- x_1} = \dfrac{\triangle y}{\triangle x} \ \ \ where \ (x_1 , \ y_1), ( x_2 , \ y_2) \ are \ points$

Here given points are: (0, -1), (3, 8)

$\rightarrow \sf slope : \dfrac{8-(-1)}{3-0} = \dfrac{9}{3} = 3$

When finding y-intercept, the value of x is 0. Here given y is -1 when x is 0.

y-intercept: -1 or (0, -1)

6 0

2 years ago

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