there are valence electrons 3 in group 10.
The hybrid orbital of this molecule is 
. Hence, option C is correct.
<h3>What is hybridisation?</h3>
Hybridization is defined as the concept of mixing two atomic orbitals to give rise to a new type of hybridized orbitals.
In this compound, a hybrid orbital makes I-O bonds. Due to hybridization iodate should have tetrahedral geometry but because of the presence of lone pair of electrons the shape of 
the ion is pyramidal.
The hybrid orbital of this molecule is . Hence, option C is correct.
Learn more about hybridisation here:
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Xylene moles =\frac{17.12}{106.16×1000}=0.00016moles=
106.16×1000
17.12
=0.00016moles
Moles of CO_2 =\frac{56.77}{44.01×1000}=0.0013CO
2
=
44.01×1000
56.77
=0.0013
Moles of H_2O= =\frac{14.53}{18.02×1000}=0.0008H
2
O==
18.02×1000
14.53
=0.0008
Moles ratios
\frac{0.0013}{0.0008}=1.625
0.0008
0.0013
=1.625
\frac{0.0008}{0.0008}=1
0.0008
0.0008
=1
Hence molecular fomula
The empirical formula is C 4H 5.
The molecular formula C8H10
Answer:
P-block metals have classic metal characteristics like they are shiny, they are good conductors of heat and electricity, and they lose electrons easily. These metals have high melting points and readily react with nonmetals to form ionic compounds.
Explanation:
<em>Answer:</em>
- The concentration of new solution will be 1×10∧-7 M.
<em>Solution:</em>
<em>Data Given </em>
given mass of fluoxymesterone =16.8mg = 0.0168 g
molar mass of fluoxymesterone = 336g/mol
vol. of fluoxymesterone = 500.0 ml = 0.500 L
Stock Molarity of fluoxymesterone = (0.0168/336)÷0.500 = 1×10∧-4 M
So applying dilution formula
Stock Solution : New Solution
M1.V1 = M2.V2
( 1×10∧-4 M) × (1×10∧-6 L) = M2 × 0.001 L
[( 1×10∧-4) × (1×10∧-6)]÷[0.001] = M2
1 × 10∧-7 = M2
<em>Result:</em>
- The concentration of new solution M2 will be 1 × 10∧-7
