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tamaranim1 [39]
3 years ago
15

Which of the following is not an example of a unit? time second meter teaspoon

Chemistry
1 answer:
Arte-miy333 [17]3 years ago
8 0
I think its time isn't a unit
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I am 90 percent positive that the answer is the first option "Its results are inconsistent over experiments"  

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3 years ago
(a) What is the charge density of an ion, and what two properties of an ion affect it?
olga nikolaevna [1]

Charge density is the ratio of the charge of ions to the volume of ions.

<h3> Factor affecting charge density</h3>

It depends on the following properties of ion as

  • Charge on the ion.
  • Volume of the ions.

The lithium ion, Li⁺, has half of the radius of the potassium ion, K⁺. That is why, Li⁺ have a electric field 4 times stronger than the electric field of K⁺ and thus it have 4 times stronger force of attraction.

All the ions: Li⁺, Na⁺, K⁺, Rb⁺, Cs⁺, have the similar electric charge +1.6×10⁻¹⁹ C. As we know that, volume is directly proportional to the third power of their radius. Therefore, smaller ions have less charge density than bigger one.

We can say that charge density decreases down across period due to decrease in the radius which further reduces the volume of ions.

Charge density increases along group due to increase in the radius which further increases the volume of ions.

Thus, we can say that charge density depends on the charge and volume of the ions.

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brainly.com/question/15810178

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6 0
2 years ago
If suddenly the force of gravity of the sun stopped acting on the planets, in what kind of path would the planets move?
e-lub [12.9K]
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3 years ago
Suppose you have 1.00 l of an aqueous buffer containing 60.0 mmol acetic acid (pka = 4.76) and 40.0 mmol acetate. what volume of
butalik [34]
Required pH = 4.93
- OH⁻ from NaOH reacts with CH₃COOH giving CH₃COO⁻ and H₂O 
- Let the volume of 3.5 M NaOH be x ml
Moles of NaOH = Moles of OH⁻ = Molarity * x ml = 3.5x mmol
- The reaction table for moles is as follows:
                   CH₃COOH + OH⁻ →  CH₃COO⁻ + H₂O
Initial               60             3.5x          40
Change         -3.5x         -3.5x         +3.5x
Final            (60-3.5x)       0           (40+3.5x)
- Substitute in Henderson equation and solve for x:
pH = pKa + log \frac{[CH_{3}COO^-]}{[CH_3COOH]}
4.93 = 4.76 + log \frac{(40+3.5x)}{(60-3.5x)}
0.17 = log \frac{(40+3.5x)}{(60-3.5x)}
\frac{(40+3.5x)}{(60-3.5x)} = 1.479
x = 5.62 ml NaOH required 
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3 years ago
1 Which type of front is least likely to be associated with rainfall?
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3 years ago
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