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Novay_Z [31]
3 years ago
13

On which variable does magnetic flux depend?A) the magnetic fieldB)the orientation of the field with respect to the region throu

gh which it passesC)the area of a region through which magnetic field passesD)all of theseE)none of these
Physics
1 answer:
hram777 [196]3 years ago
4 0

Answer:

D) All of these

Explanation:

The magnetic flux through a coil of wire is given by:

\Phi = BA cos \theta

where

B is the intensity of the magnetic field

A is the area enclosed by the coil

\theta is the angle between the direction of B and the normal to the area of the coil

Therefore, we see that the magnetic flux depends on all these quantities:

A) the magnetic field

B)the orientation of the field with respect to the region through which it passes

C)the area of a region through which magnetic field passes

So, the correct answer is

D) All of these

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A projectile is launched straight up from a height of 960 feet with an initial velocity of 64 ft/sec. Its height at time t is h(
Natasha2012 [34]

Answer:

a) t=2s

b) h_{max}=1024ft

c) v_{y}=-256ft/s

Explanation:

From the exercise we know the initial velocity of the projectile and its initial height

v_{y}=64ft/s\\h_{o}=960ft\\g=-32ft/s^2

To find what time does it take to reach maximum height we need to find how high will it go

b) We can calculate its initial height using the following formula

Knowing that its velocity is zero at its maximum height

v_{y}^{2}=v_{o}^{2}+2g(y-y_{o})

0=(64ft/s)^2-2(32ft/s^2)(y-960ft)

y=\frac{-(64ft/s)^2-2(32ft/s^2)(960ft)}{-2(32ft/s^2)}=1024ft

So, the projectile goes 1024 ft high

a) From the equation of height we calculate how long does it take to reach maximum point

h=-16t^2+64t+960

1024=-16t^2+64t+960

0=-16t^2+64t-64

Solving the quadratic equation

t=\frac{-b±\sqrt{b^{2}-4ac}}{2a}

a=-16\\b=64\\c=-64

t=2s

So, the projectile reach maximum point at t=2s

c) We can calculate the final velocity by using the following formula:

v_{y}^{2}=v_{o}^{2}+2g(y-y_{o})

v_{y}=±\sqrt{(64ft/s)^{2}-2(32ft/s^2)(-960ft)}=±256ft/s

Since the projectile is going down the velocity at the instant it reaches the ground is:

v=-256ft/s

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