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g100num [7]
3 years ago
13

You leave on a 450 miles trip in order to attend a meeting that will start 10.8 hours after you begin your trip. Along the way y

ou plan to stop for dinner. If the fastest you can safely drive is 55 mi/h, what is the longest time you can spend over dinner and still arrive just in time for the meeting? Select one: O a. 0.8 h b. You can't stop at all. c. 2.6 h d. 2.8 h 0
Physics
1 answer:
Lorico [155]3 years ago
5 0

Answer:2.6 h

Explanation:

Given

Total Trip distance=450 miles

Meeting starts after 10.8 hours

safe Fastest speed is  55 mi/h

so if he drives all the to the meeting with max speed then it takes =\frac{450}{55}=8.181 h

and total allowable time is 10.8

Therefore longest time he can spend over dinner is 10.8-8.181 \approx 2.6 hours

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V = k * Q / r 

where v is the voltage of the point, k is a constant, Q is charge of the point measured in coloumbs and r is the distance. 
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Point 1: 
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Suppose light from a 632.8 nm helium-neon laser shines through a diffraction grating ruled at 520 lines/mm. How many bright line
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1 bright fringe every 33 cm.

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