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Arturiano [62]
3 years ago
6

How is ocean exploration beneficial to everyone?

Physics
1 answer:
xeze [42]3 years ago
7 0

Unlocking the mysteries of deep-sea ecosystems can reveal new sources for medical drugs, food, energy resources, and other products. Information from deep-ocean exploration can help predict earthquakes and tsunamis and help us understand how we are affecting and being affected by changes in Earth's environment.

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2.5 years into minutes?<br><br>​
Mnenie [13.5K]
Is it 1314000 Or something
8 0
3 years ago
Why does Doug need to adjust his workouts when they seem too easy?
Aleonysh [2.5K]
Doug needs to change the <em>exercises </em>he is doing. Your body begins to become accustomed to what you do, and if you do the same thing every single time - you will stop making progress, and they'll simply become easy.

However, if you walk into the gym and your body is expecting you to just go over and bench press some, go rock some curls, head over to the squat rack then go home - but instead you start out with some dips, then go do lunges, then attack your triceps instead of biceps, your body will be shocked! 

When you change it up, your body will react. The goal is to be comfortable being uncomfortable. Also, one of the most overlooked things in working out is the intensity. If you bring it everything you got and go to the last gut wretching rep, you'll see results. 

However, if you just leisurely do things with 4 minute rests in between - you won't see true progress.

Hopefully, this helps! =)
6 0
4 years ago
a loaded sack of total mass is 1000 gramme falls down from the floor of a lorry 200cm high, calculate the workdone by the gravit
Helen [10]

Answer:

W = 20 J

Explanation:

Given that,

The mass of a loaded sack, m = 1000 g = 1 kg

It falls down from the floor of a lorry 200 cm high, h = 2 m

We need to find the work done by the gravity. The work done by an object under the action of gravity is given by :

W = mgh

Substitute all the values,

W = 1 × 10 × 2

= 20 J

Hence, the required work done by gravity is equal to 20 J.

8 0
3 years ago
A ball of mass m= 450.0 g traveling at a speed of 8.00 m/s impacts a vertical wall at an angle of θi =45.00 below the horizontal
Mkey [24]

Answer:

   F = 20.4 i ^

Explanation:

This exercise can be solved using the ratio of momentum and amount of movement.

     I = F t = Dp

Since force and amount of movement are vector quantities, each axis must be worked separately.

X axis

Let's look for speed

      cos 45 = vₓ / v

      vₓ = v cos 45

      vₓ = 8 cos 45

      vₓ = 5,657 m / s

We write the moment

Before the crash                          p₀ = m vₓ

After the shock                            p_{f} = -m vₓ

The variation of the moment      Δp = mvₓ - (-mvₓ) = 2 m vₓ

The impulse on the x axis           Fₓ t = Δp

       

        Fₓ = 2 m vₓ / t

        Fx = 2 0.450 5.657 / 0.250

        Fx = 20.4 N

We perform the same calculation on the y axis

       sin  45 = vy / v

       vy = v sin 45

       vy = 8 sin 45

       vy = 5,657 m / s

We calculate the initial momentum   po = m v_{y}

Final moment                                      p_{f} = m v_{y}

Variations moment                             Δp = mv_{y} - mv_{y} = 0

Force in the Y-axis                             F_{y} = 0

Therefore the total force is

       F = fx i ^ + Fyj ^

       F = Fx i ^

       F = 20.4 i ^

3 0
4 years ago
A ball with a mass of 3kg is dropped from the top of a building this is 20m high. what is the velocity of the ball when it is 10
anzhelika [568]

Answer:

Velocity=14[m/s]

Explanation:

We can solve this problem by using the principle of energy conservation, where potential energy becomes kinetic energy.

In the attached image we can see the illustration of the ball falling from the height of 20 meters, at this time the potential energy will have the following value.

Ep=m*g*h\\where:\\m=3[kg]\\h=20[m]\\

Ep=3*9.81*20\\Ep=588.6[J]

When the ball passes through half of the distance (10m) its potential energy will have decreased by half as shown below.

Ep=3*9.81*10\\Ep=294.3[m]

If we know that potential energy is transformed into kinetic energy, we can find the value of speed.

Ek=\frac{1}{2} *m*v^{2} \\therefore\\v=\sqrt{\frac{Ek*2}{m} } \\v=\sqrt{\frac{294.3*2}{3} } \\\\v=14[m/s]

7 0
4 years ago
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