Answer:
Moment of the force is 20 N-m.
Explanation:
Given:
Force exerted by the person is, ![F=80\ N](https://tex.z-dn.net/?f=F%3D80%5C%20N)
Distance of application of force from the point about which moment is needed is, ![d=25\ cm=\frac{25}{100}\ m=0.25\ m](https://tex.z-dn.net/?f=d%3D25%5C%20cm%3D%5Cfrac%7B25%7D%7B100%7D%5C%20m%3D0.25%5C%20m)
Now, we know that, moment of a force 'F' about a point at a perpendicular distance of 'd' from the same point is given as the product of the force and the perpendicular distance.
Therefore, the moment of the force about the end of the claw hammer is given as:
![M=F\times d\\\\M=(80\ N)(0.25\ m)\\\\M=20\textrm{ N-m}](https://tex.z-dn.net/?f=M%3DF%5Ctimes%20d%5C%5C%5C%5CM%3D%2880%5C%20N%29%280.25%5C%20m%29%5C%5C%5C%5CM%3D20%5Ctextrm%7B%20N-m%7D)
Hence, the moment of the force exerted by the person about the end of the claw hammer is 20 N-m.