Answer:
the answer is below
Explanation:
The diagram of the problem is given in the image attached.
Mass of rod AB = (0.4 m + 0.4 m) * 3 kg/m = 2.4 kg
Mass of rod OC = (1.5 m) * 3 kg/m = 4.5 kg
Mass of plate = 10 kg/m²[ (π* 0.3²) - (π* 0.1²)] = 2.513 kg
The center of mass is:
![\hat{y}[2.4+2.513+4.5]=(0.75*4.5)+(2.513*0.5)\\\\\hat{y}=0.839\\\\I_{AB}=\frac{1}{12}*2.4*(0.4+0.4)^2= 0.128\ kg/m^2\\\\I_{OC}=\frac{1}{12}*4.5*(1.5)^2= 3.375\ kg/m^2\\\\I_{Gplate}=\frac{1}{2}*(\pi*0.3^2*10)*(0.3)^2-\frac{1}{2}*(\pi*0.1^2*10)*(0.1)^2= 0.126\ kg/m^2\\\\I_{plate}=I_{Gplate}+md^2=0.126+2.513(1.8^2)=8.27\ kg/m^2\\\\I_o=I_{plate}+I_{AB}+I_{OC}\\\\I_{o}=0.128+3.375+8.27=11.773\ kg/m^2 \\\\I_G=I_o-m_{tot}\hat{y}^2\\\\I_G=11.773-(9.413*0.839^2)\\\\I_G=5.147\ kg/m^2](https://tex.z-dn.net/?f=%5Chat%7By%7D%5B2.4%2B2.513%2B4.5%5D%3D%280.75%2A4.5%29%2B%282.513%2A0.5%29%5C%5C%5C%5C%5Chat%7By%7D%3D0.839%5C%5C%5C%5CI_%7BAB%7D%3D%5Cfrac%7B1%7D%7B12%7D%2A2.4%2A%280.4%2B0.4%29%5E2%3D%200.128%5C%20kg%2Fm%5E2%5C%5C%5C%5CI_%7BOC%7D%3D%5Cfrac%7B1%7D%7B12%7D%2A4.5%2A%281.5%29%5E2%3D%203.375%5C%20kg%2Fm%5E2%5C%5C%5C%5CI_%7BGplate%7D%3D%5Cfrac%7B1%7D%7B2%7D%2A%28%5Cpi%2A0.3%5E2%2A10%29%2A%280.3%29%5E2-%5Cfrac%7B1%7D%7B2%7D%2A%28%5Cpi%2A0.1%5E2%2A10%29%2A%280.1%29%5E2%3D%200.126%5C%20kg%2Fm%5E2%5C%5C%5C%5CI_%7Bplate%7D%3DI_%7BGplate%7D%2Bmd%5E2%3D0.126%2B2.513%281.8%5E2%29%3D8.27%5C%20kg%2Fm%5E2%5C%5C%5C%5CI_o%3DI_%7Bplate%7D%2BI_%7BAB%7D%2BI_%7BOC%7D%5C%5C%5C%5CI_%7Bo%7D%3D0.128%2B3.375%2B8.27%3D11.773%5C%20kg%2Fm%5E2%20%5C%5C%5C%5CI_G%3DI_o-m_%7Btot%7D%5Chat%7By%7D%5E2%5C%5C%5C%5CI_G%3D11.773-%289.413%2A0.839%5E2%29%5C%5C%5C%5CI_G%3D5.147%5C%20kg%2Fm%5E2)
The correct answer is "All of the above".
In fact, electromagnetic induction occurs when there is a change of the magnetic flux through the area enclosed by a circuit (in this case, the area enclosed by the wire loop).
The magnetic flux
through a certain surface is given by
(1)
Where B is the intensity of the magnetic field, A is the area enclosed by the circuit and
is the angle between the direction of the field B and the perpendicular to the area.
In the first situation, the magnet is getting closer to the loop, so the magnetic flux through the area enclosed by the wire is increasing (because the intensity of the magnetic field B is increasing). Situation 2) is the opposite case: the wire loop is moving away from the magnet, so the intensity of the magnetic field B is decreasing, and therefore the magnetic flux is decreasing as well.
Finally, in the third situation the wire loop is rotating. Here the distance between the loop and the magnet is not changing, but remember that the magnetic flux depends also on the angle between the direction of the magnetic field and the perpendicular (formula 1), and so since the wire loop is rotating, than this angle is changing, therefore the magnetic flux is changing as well.
F = m * a
a = F / m = 2.050.000 N / 40.000 kg ( 1 N = 1 kgm/s² )
a = 51.25 m/s²
Answer:
D (density) = Mass / Volume
V (ice) = Mass / Density = 50000 g / .92 kg / L
V = 50 kg / .92 kg / L
1 Liter of water weighs 1 kilogram = 50 L weighs 50000 g
V = 54.3 L the mass does not change upon the change of phase (freezing)
:<span> </span><span>Under the assumption that a cell is made up of two concentric spheres you find the surface are of the inside sphere which will be your A.
You already have your separation and dielectric constant so just use the formula you stated towards the end of your question and you get 8.93x10^-11 Farads which is about 89pF</span>
