3 Edward is scuba diving. He stops 14.3 m below the surface to look at a fish.
1 answer:
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Answer:
P(A | F) = 81.81%
There is 81.81% probability that worker was taught by method A given that he failed to learn it correctly.
Step-by-step explanation:
The failure rate is 15% for A which means that
P(F | A) = 0.15
The failure rate is 5% for B which means that
P(F | B) = 0.05
Method B is more expensive and hence is used only 40% of the time which means that
P(B) = 0.40
Which means that A is used the other 60% of the time
P(A) = 0.60
A worker is taught the skill by one of the methods but fails to learn it correctly.
We are asked to find the the probability that he was taught by method A.
So that means we want to find out
P(A | F) = ?
We know that according to Baye's rule,
Substitute the given probabilities into the above equation
Therefore, there is 81.81% probability that worker was taught by method A given that he failed to learn it correctly.
Using the normal distribution, it is found that there is a 0.1357 = 13.57% probability that the total amount paid for these second movies will exceed $15.00.
In a <em>normal distribution</em> with mean and standard deviation
, the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
- For n instances of a normal variable, the mean is
and the standard error is
In this problem:
- Mean of $0.47, standard deviation $0.15, hence
- 30 instances, hence
The probability is <u>1 subtracted by the p-value of Z when X = 15</u>, hence:
Considering the n instances:
has a p-value of 0.8643.
1 - 0.8643 = 0.1357.
0.1357 = 13.57% probability that the total amount paid for these second movies will exceed $15.00.
A similar problem is given at brainly.com/question/25769446