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emmasim [6.3K]
3 years ago
10

How much do you expect gas to cost in 2020?

Business
2 answers:
mina [271]3 years ago
4 0
Atleast 5 dollars because of how there is a limited supply of gasoline today
sergij07 [2.7K]3 years ago
4 0
4.98 because every thing in 2020 is probably going to cost double of what it is today
You might be interested in
In many​ corporations, there is​ "separation of ownership from​ control." what does this​ mean
sesenic [268]
<span>This means shareholders own the corporation, but it is controlled by managers.</span>
3 0
3 years ago
"You need to have $15,000 in five years to pay off a home equity loan. You can invest in an account that pays 5.75 percent compo
Nana76 [90]

Answer:

I have to invest $11364.

Explanation:

The formula of Compound Interest is:

A = P(1+\frac{r}{n})^{nt}

where A = Amount

P = Principle

r = rate

n = Number of Compounding per year

t = total number of year

Here, A = 15000, r = 5.75% = 0.0575, n = 4(quarterly), and t = 5.

Putting all these values in above formula:

15000 = P(1+\frac{0.0575}{4})^{4\times5}

⇒ 15000 = P(\frac{4.0575}{4})^{20}

⇒ 15000 = P(1.014)^{20}

⇒ 15000 = P(1.320)}

⇒ P = 11364

Hence, I have to invest $11364 for 5 years.

4 0
3 years ago
Norma Smith is the controller of Bramble Corporation and is responsible for the preparation of the year-end financial statements
melisa1 [442]

Answer:

Current liability refers to the short term obligations of the firm which need to be settled down within a period of one year or within a normal operating cycle.

(a) $0 would be reported as current liability, as it is not a current liability. It is a contingent liability.

(b) The amount of current liability is $192,900 because it is a liability of a firm to pay bonuses to the employees.

(c) The amount of current liability is as follows:

= $900,000 × 0.08 × (1/12)

= $6,000

Payment of interest on loan is a liability of the firm.

(d) $0 would be indicated in current liability, because provision for doubtful accounts is subtracted from the total accounts receivable to determine the net account receivables.

(e) Proposed dividend is a part of current liability and the amount of dividend to be shown as current liability is as follows:

= Dividend per share × No. of shares outstanding

= $3.50 per share × 41,810

= $146,335

(f) Customer advances is a current liability and the amount of customer advances to be reported in current liability is calculated as follows:

= Customer advances - Amount earned this year

= $193,100 - $57,900

= $135,200

6 0
3 years ago
MJ LTD is expected to grow at various rates over the next five years. The company just paid a $1.00 dividend. The company expect
Black_prince [1.1K]

Answer:

$21.859

Explanation:

According to the scenario, computation of the given data are as follow:-

Present Value = D0 × (1 + growth rate)^time ÷ (1 + Required Rate of Return)^time period

1st Year PV = $1 × (1 + 0.20)^1 ÷ (1+ 0.12)^1

                  = 1.20 ÷ 1.12

                 = 1.071

2nd Year PV = $1 × (1 + 0.20)^2 ÷ (1+ 0.12)^2

                   = $1 × (1.44) ÷ 1.254

                  = $1.148

3rd Year PV = $1 × ( 1 + 0.20)^2 × (1 + 0.10) ÷ (1 + 0.12)^3

                    = $1 × (1.44) × (1.10) ÷ 1.405

                     = $1.127

4th Year PV = $1 × ( 1 + 0.20)^2 × (1 + 0.10)^2 ÷ ( 1 +0.12)^4

                    = $1 × (1.44) × (1.21) ÷ 1.574

                     = $1.107

5th Year PV = $1 × (1 + 0.20)^2 × ( 1 +0.10)^3 ÷ (1 + 0.12)^5

                     = $1 × (1.44) × (1.331) ÷ 1.762

                     = $1.088

6th Year PV = $1 × (1 + 0.20)^2 × (1 + .10)^3 × (1.05) ÷ [(0.12 - 0.05) × (1+.12)^5]

= $1 × (1.44) × (1.331) × (1.05) ÷ (0.07) ×  (1.762)

= $2.012 ÷ 0.1233

= $16.318

Now

Share’s Current Value is

= $1.071 + $1.148 + $1.127 + $1.107 + $1.088 + $16.318

= $21.859

We simply applied the above formula

5 0
3 years ago
A researcher wants to test the order of integration of some time series data. He decides to use the DF test. He estimates a regr
pav-90 [236]

Answer:

a) H0: u = presence of a unit root

   HA: u ≠ presence of a unit root  ( i.e. stationary series )

b) t stat = -0.064

c) We will reject the Null hypothesis and the next step will be to accept the alternative hypothesis

d) It is not valid to compare the estimated t stat with the corresponding critical value because a random walk is non-stationary while the difference is stationary because it is white noise

Explanation:

<u>a) stating the null and alternative hypothesis</u>

H0: u = presence of a unit root

HA: u ≠ presence of a unit root  ( i.e. stationary series )

<u>b) performing the test </u>

critical value = -2.88

T stat = coefficient / std error

          = -0.02 / 0.31  = -0.064

c) From the test, the value of T stat > critical value we will reject the Null hypothesis hence the next step will be to accept the alternative hypothesis

d) It is not valid to compare the estimated t stat with the corresponding critical value because a random walk is non-stationary while the difference is stationary because it is white noise

   

5 0
3 years ago
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