Answer:
94.13 ft/s
Explanation:
<u>Given:</u>
- = time interval in which the rock hits the opponent = 10 s - 5 s = 5 s
- = distance to be moved by the rock long the horizontal = 98 yards
- = displacement to be moved by the rock during the time of flight along the vertical = 0 yard
<u>Assume:</u>
- = magnitude of initial velocity of the rock
- = angle of the initial velocity with the horizontal.
For the motion of the rock along the vertical during the time of flight, the rock has a constant acceleration in the vertically downward direction.
Now the rock has zero acceleration along the horizontal. This means it has a constant velocity along the horizontal during the time of flight.
On dividing equation (1) by (2), we have
Now, putting this value in equation (2), we have
Hence, the initial velocity of the rock must a magnitude of 94.13 ft/s to hit the opponent exactly at 98 yards.
The answer is 2,125,440 m/s
Any bridge is subject to three different types of forces: the dead load, the live load, and the dynamic load. The weight of the bridge itself is discussed in the first of these words.
<h3>What are the 4 different types of forces?</h3>
Any of the four fundamental forces in physics—gravitational, electromagnetic, strong, and weak—that control how objects or particles interact as well as how some particles decay—is referred to as a fundamental force, also known as a fundamental interaction.
<h3>What primary force is acting on the bridge?</h3>
Compression and tension are the two main forces that are ever-present on a bridge. A force that compresses or shortens the object it is acting on is known as a compressive force. A force known as tension or tensile force works to stretch or expand the object it is acting on.
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When one substance dissolves into another, a solution is formed. A solution is a homogeneous mixture consisting of a solute dissolved into a solvent . The solute is the substance that is being dissolved, while the solvent is the dissolving medium.