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Pachacha [2.7K]
3 years ago
12

A hot iron ball of mass 200 g is cooled to a temperature of 22°C. 6.9 kJ of heat is lost to the surroundings during the process.

What was the initial temperature of the ball? (ciron = 0.444 J/g°C)
A)
23°C
B)
78°C
C)
100°C
D)
155°C
Physics
2 answers:
qaws [65]3 years ago
5 0
Heat lost or gained, H = mc(θ₂ - θ₁) 
Where m = mass, c = Specific heat capacity, θ₂= final temperature, θ₁ = initial temperature

m = 200g, c = 0.444 J/g°C, θ₁ = 22 °C  (Since it was cooled).

H = 6.9 kj = 6.9 *1000J = 6900 J

6900 = 200*0.444* (θ₂ - 22)

6900/(200*0.444)  =  θ₂ - 22

77.70 = θ₂ - 22

θ₂ - 22 = 77.7

θ₂      =  77.7 + 22 = 99.7

So initial temperature before cooling ≈ 100°C .  Option C.


vodomira [7]3 years ago
4 0

Answer:

The answer is C) 100°C

Explanation:

It's on USATestprep.

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