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Volgvan
4 years ago
6

A teacher did an experiment to show the movement of particles in solids, liquids, and gases. The experimental set-up is shown be

low:
The dryer speed can be adjusted at low, medium, and high to represent each state of matter. Which combination of the state of matter and the corresponding dryer speed is correct?

A) liquid = low; solid = medium; gas = high.
B) solid = low; liquid = medium; gas = high.
C) liquid = low; gas = medium; solid = high.
D) gas = low; liquid = medium; solid = high.

Physics
1 answer:
ELEN [110]4 years ago
8 0

Answer: Option (B) is the correct answer.

Explanation:

In a solid, molecules are held together by strong intermolecular forces of attraction. As a result, they are unable to move from their initial place but they can vibrate at their mean position.

Hence, in solid substances the molecules have low kinetic energy.

Whereas in liquids, the molecules are held by less strong intermolecular forces of attraction as compared to solids. Due to which they are able to slide past each other. Hence, they have medium kinetic energy.

In gases, the molecules are held by weak Vander waal forces. Hence, they have high kinetic energy due to which they move rapidly from one place to another leading to more number of collisions.

Hence, gases are able to expand more rapidly as compared to liquids.

Thus, we can conclude that out of the given options solid = low; liquid = medium; gas = high, combination of the state of matter and the corresponding dryer speed is correct.

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What is electron affinity?​
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Answer:

The electron affinity of an atom or molecule is defined as the amount of energy released when an electron is attached to a neutral atom or molecule in the gaseous state to form a negative ion.

4 0
3 years ago
Suppose a skydiver (mass = 75 kg) is falling toward the Earth. When the skydiver is 100 m above the Earth he is moving at 60 m/s
Andrej [43]

Answer:

  Potential energy = 73.575 kJ

  Kinetic energy = 135kJ

  Total mechanical energy = 208.575 kJ

Explanation:

   The potential energy of a body is given by the expression, PE = mgh, where m is the mass of the body, g is the acceleration due to gravity value and h is the height of the body.

  The kinetic energy of a body is given by KE=\frac{1}{2} mv^2, where v is the velocity and m is the mass of body.

  Total mechanical energy = Kinetic energy + Potential energy

  KE=\frac{1}{2} mv^2=\frac{1}{2} *75*60^2= 135000J = 135kJ

  PE = mgh = 75*9.81*100 = 73575 J = 73.575 kJ

  Total mechanical energy = Kinetic energy + Potential energy = 135+73.575

                                             = 208.575 kJ    

4 0
3 years ago
Two cars of the same mass have different velocities. Which car has more momentum?
never [62]

<u>Answer:</u>

<h3>The car with the higher velocity would have a more impactful momentum.</h3>
7 0
3 years ago
Rony fills a bucket with water and whirls it in a vertical circle to demonstrate that the water will not spill from the bucket a
Romashka-Z-Leto [24]

Answer:

0 N, 3.49 m/s

Explanation:

Draw a free body diagram for the bucket at the top of the swing.  There are two forces acting on the bucket: weight and tension, both downwards.

If we take the sum of the forces in the radial direction, where towards the center is positive:

∑F = ma

W + T = m v² / r

The higher the velocity that Rony swings the bucket, the more tension there will be.  The slowest he can swing it is when the tension is 0.

W = m v² / r

mg = m v² / r

g = v² / r

v = √(gr)

Given that r = 1.24 m:

v = √(9.8 m/s² × 1.24 m)

v = 3.49 m/s

8 0
3 years ago
A 2-kg cart, traveling on a horizontal air track with a speed of 3m/s, collides with a stationary 4-kg cart. The carts stick tog
ladessa [460]

Answer:

The impulse exerted by one cart on the other has a magnitude of 4 N.s.

Explanation:

Given;

mass of the first cart, m₁ = 2 kg

initial speed of the first car, u₁ = 3 m/s

mass of the second cart, m₂ = 4 kg

initial speed of the second cart, u₂ = 0

Let the final speed of both carts = v, since they stick together after collision.

Apply the principle of conservation of momentum to determine v

m₁u₁ + m₂u₂ = v(m₁ + m₂)

2 x 3 + 0 = v(2 + 4)

6 = 6v

v = 1 m/s

Impulse is given by;

I = ft = mΔv = m(

The impulse exerted by the first cart on the second cart is given;

I = 2 (3 -1 )

I = 4 N.s

The impulse exerted by the second cart on the first cart is given;

I = 4(0-1)

I = - 4 N.s (equal in magnitude but opposite in direction to the impulse exerted by the first).

Therefore, the impulse exerted by one cart on the other has a magnitude of 4 N.s.

8 0
4 years ago
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