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serious [3.7K]
3 years ago
14

In 2002, Colorado was suffering from extreme drought. Which technology will help Colorado reduce the effects of future droughts?

Physics
2 answers:
Vika [28.1K]3 years ago
8 0
I would say C: Dam

Sea walls and levees stop water from overflowing onto something. Which can we good but has no impact on droughts.

Storm shelters wont impact droughts either. They are men't to protect people from storms.

A Dam on the other hand can contain and keep water in one given place. Which will save water, to be used to prevent future droughts.

Hope this helps!
Brainliest is appreciated if you feel its deserved!
Arada [10]3 years ago
4 0
The drought problem in Colorado will be reduced if the people living in there will build dams. Dams are used to store water in a long period of time. When the dam is full, it will release water that are necessary in drought season. These dams will store huge amount of water which will be a supply in the long period of drought in Colorado.
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If a car is traveling 27 meters in 3 seconds, what is its speed?
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9 because speed=distance/ time
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2 years ago
The Pasig Revolving Tower has an estimated height of 45.23 meters. How high is it in yard? ​
hichkok12 [17]

Answer:

50.26

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6 0
3 years ago
A shallow groove on the surface of the cortex is called a ________.
Juli2301 [7.4K]

Answer:

sulcus

Explanation:

A sulcus is an indentation or depression in the brain that causes it to look like it  ridges or folds

Cerebral sulci and fissures are grooves between the adjacent gyri on the surface of the cerebral hemispheres.

Sulci can be basically can be divided into three basic function

limiting sulcus: This happens to  develop between areas differing in structure and function, for example central sulcus

axial sulcus: This develops along the axis of a rapidly growing/developing area (e.g. calcarine sulcus)

operculated sulcus: a sulcus may be between two structurally-different areas and a third sulcus may lie in its wall and does not appear on the surface (e.g. lunate sulcus)

3 0
3 years ago
Define resistance and describe what would happen to a lightbulb if the voltage increase but the resistance stay the same?
artcher [175]

The first question is how much of a voltage increase are we looking at. If it has a 110 voltage rating and you put it across a 220 source, you will see one flash and then the bulb is no more. Nothing will revive it.

If it is rated at 110 and you put 130 across it, there's no problem but the bulb will burn out sooner than it would if you just put 110 across it.

So you raise the voltage and the resistance stays the same, the current will increase. That's why it will burn out sooner.

V = I * R

The equation is a direct variation. If the voltage goes up the current goes up. If the voltage goes down, the current goes down providing that the resistance stays the same in both cases.

The second question is what is resistance? Resistance in Electricity is the ability of an electric current to go in one direction freeing up as many electrons as it can. The MORE free electrons, the lower the resistance. The FEWER free electrons the higher the resistance.

Here' the kicker. Ready? More and Less are probably the two most important words in beginning science.

The <u><em>More</em></u> the resistance, the <em><u>Less</u></em> the current flow. That's a really important consideration in battery drain in a watch (or modern day calculator). The More the Battery Drain, the Less time it will last.

Always be careful when more and Less are around.

7 0
3 years ago
An object on a vertical spring oscillates up and down in simple harmonic motion with an angular frequency of 25.7 rad/s. Calcula
Sergio [31]

Answer:

The distance by which the spring stretches is 1.48 cm.

Explanation:

Given that,

An object on a vertical spring oscillates up and down in simple harmonic motion with an angular frequency of 25.7 rad/s, \omega=25.7\ rad/s

We know that angular frequency in SHM is given by :

\omega=\sqrt{\dfrac{k}{m}} \\\\\omega^2=\dfrac{k}{m}\\\\\dfrac{k}{m}=(25.7)^2.............(1)

When the object is allowed to hang stationary from it, the force due to spring is balanced by its weight. Such that :

kd=mg\\\\d=\dfrac{g}{(k/m)}

From equation (1) :

d=\dfrac{9.8}{(25.7)^2}\\\\d=0.0148\ m\\\\d=1.48\ cm

So, the distance by which the spring stretches is 1.48 cm.

6 0
3 years ago
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