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vladimir1956 [14]

3 years ago

10

A subducting oceanic plate

1 answer:

beks73 [17]3 years ago

4 0

Maybe this would help understand it better.

<span>Tectonic plates can transport both continental crust and oceanic crust, or they may be made of only one kind of crust. Oceanic crust is denser than continental crust. At a subduction zone, the oceanic crust usually sinks into the mantle beneath lighter continental crust</span>

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Flower bed is filled with five types of flowers. Which placement of the flowers represents the highest entropy?

mars1129 [50]

Answer:

B

Explanation:

3 0

3 years ago

Read 2 more answers

An electric field of 710,000 N/C points due west at a certain spot. What is the magnitude of the force that acts on a charge of

Anni [7]

Answer:

The magnitude of force is $4.26\times 10^{- 6} N$

Solution:

As per the question:

The strength of Electric field due west at a certain point, $\vec{E_{w}} = 710,000 N/C$

Charge, Q = - 6 C

Now, the force acting on the charge Q in the electric field is given by:

$\vec{F} = Q\vec{E_{w}}$

$\vec{F} = -6\times 710,000 = - 4.26\times 10^{- 6} N$

Here, the negative sign indicates that the force acting is opposite in direction.

5 0

3 years ago

A light bulb in a camper’s flashlight is labeled 4.1 V, 0.40 A. Find the equivalent current if three of these light bulbs are co

Gnesinka [82]

Explanation:

first rule of parallel circuits : the voltage is the same in the whole circuit, no matter where we measure.

so, we have 1.5V at every bulb.

second rule of parallel circuits : the total current is the sum of the individual branch currents.

so, if the battery really allows it, then we have 3 times 0.4 A = 3×0.4 = 1.2 A as current in the circuit.

5 0

2 years ago

Two particles move along an x axis. The position of particle 1 is given by x ! 6.00t 2 # 3.00t # 2.00 (in meters and seconds); t

s344n2d4d5 [400]

Answer:

15.6m/s

Explanation:

V1= $\frac{dx}{dt}=\frac{d}{dt}(6t^{2}+3t+2)$ because the derivate of the position is the velocity

V1=12t+3

V2=20+ $\int\limits^_ {} \,$ -8t because the integral of the acceleration is the velocity

V2= $20-4t^{2}$

V1=V2 to see when the velocities of particles match

12t+3=20-4t^2

4t^2+12t-17=0 we resolve this with $\frac{-b+-(\sqrt{b^{2} -4ac} )}{2a}$

and we take the positif root

t=1.05 sec

if we evaluate the velocity (V1 or V2) the result is 15.6m/s

7 0

3 years ago

Hey can someone please help me and can u show your work plz plz plz plz

Tju [1.3M]

Answer:

Good luck

Explanation:

4 0

3 years ago