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saul85 [17]
3 years ago
14

State and prove Newton's second law of motion ​

Physics
1 answer:
LiRa [457]3 years ago
5 0

Answer:

HOPE IT HELP YOU A LOT :)

I prove it also .

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A 20.0-kg traffic light hangs midway on a cable between two poles 30.0 meters apart. If the sag in the cable is 0.40 meters, wha
hammer [34]

Answer:

the tension in each side of the cable is 3677.57 N

Explanation:

given data

traffic light = 20 kg

cable between two poles = 30 m

sag in the cable = 0.40 m

solution

by the free body diagram

tan θ = \frac{0.4}{15}    .............1

θ = 1.527 °

and

tension = mg

The net force is along x - axis is express as

T2 cosθ = T1 cosθ     .................2

so T2 - T1     ..............3

and

when we take it along y  axis  that is express as

( T1 + T2) sinθ = mg    ...................4

so by equation 3 we put here

2 × T1 sin(1.527) = 20 × 9.8  

T1 = 3677.57 N

7 0
4 years ago
Which ball moved at the same speed as Ball 3?
Luden [163]

Answer:

you forgot to attach the image

3 0
3 years ago
Read 2 more answers
A uniform rod of length L is pivoted at L/4 from one end. It is pulled to one side through a very small angle and allowed to osc
ludmilkaskok [199]

Answer:

T= 4.24sec

Explanation:

We are going to use the formula below to calculate.

T=2\pi \sqrt{\frac{L}{g} }

Where T is period

           L is length of rod

       g is acceleration due to gravity =     9.8m/s^{2}

From the problem, the rod is pivoted at 1/4L which means that three quarter of the rod was used for the oscillation. lets call this L_{O}

L_{O} = 3/4 * 5.95m

        = 4.4625m

thus   T=2\pi \sqrt{\frac{L_{O} }{g} }

          T=2\pi \sqrt{\frac{4.4625 }{9.8} }

          T= 4.24sec

8 0
4 years ago
What happens to jetstream’s as they get closer to the equator
MAVERICK [17]

Answer:They stop because jet streams follow boundaries between hot and cold air.

Explanation:

6 0
4 years ago
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Calculate the energy equivalent in joules of the mass of a proton
Tamiku [17]
The problem should only have one part to it, but this one has two.
Before I can do the mass/energy conversion, I have to go and
look up the proton mass for myself ... go out and collect the straw
to make my bricks, as it were.  As if the fabulous bounty of 7 points
makes it worth it.  They make us do everything around here.

OK.  In my Physics book⁽¹⁾, the proton rest mass is

                       1.67 x 10⁻²⁷  kg.

The formula that relates mass to the equivalent energy is

                        E = m c²  .

The method of applying the formula is known as "plug in what you know",
as follows:

                       E  =  (mass) x (speed of light)²

                          =  (1.67 x 10⁻²⁷ kg) x (3 x 10⁸ m/s)²

                         =  (1.67 X 10⁻²⁷ Kg) x (9 x 10¹⁶ m²/s²) 

                          =        (1.5 x 10⁻¹⁰)  (kg-m²/s²)

                          =            1.5 x 10⁻¹⁰  joule .                           
____________________________________

⁽¹⁾  Halliday, David and Resnick, Robert, Physics , John Wiley & Sons,
Inc., 1960,  inside front cover, "SELECTED PHYSICAL CONSTANTS".
8 0
4 years ago
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