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Serjik [45]
3 years ago
8

Electrons are allowed "in between" quantized energy levels, and, thus, only specific lines are observed. The energies of atoms a

re not quantized. The energies of atoms are quantized. Electrons are not allowed "in between" quantized energy levels, and, thus, only specific lines are observed. When an electron moves from one energy level to another during absorption, a specific wavelength of light (with specific energy) is emitted. When an electron moves from one energy level to another during emission, a specific wavelength of light (with specific energy) is emitted.
Physics
1 answer:
lawyer [7]3 years ago
5 0

Answer:

This is because The energies of atoms are quantized.

Electrons are allowed "in between" quantized energy levels, and, thus, only specific lines are observed

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A 12.0-kg package in a mail-sorting room slides 2.00 m down a chute that is inclined at 53.0° below the horizontal. The coeffici
zvonat [6]

Answer

given,

mass of the package = 12 kg

slides down distance = 2 m

angle of inclination = 53.0°

coefficient of kinetic friction = 0.4

a) work done on the package by friction is

              W_f = -μk R d

                   = -μk (mg cos 53°)(2.0)

                   =-(0.4)(8.0 )(9.8)(cos 53°)(2.0)

                   = -37.75 J

b)

work done on the package by gravity is

             W_g = m (g sin 53°) d

                   = (8.0 )(9.8 )(sin 53°)(2.0 )

                   =125.23 J

c)

the work done on the package by the normal force is

             W_n = 0

d)

the net work done on the package is

           W = -37.75 + 125.23 + 0

           W = 87.84 J

7 0
3 years ago
The knee extensors insert on the tibia at an angle of 30 degrees (from the longitudinal axis of the tibia), at a distance of 3 c
Reika [66]

Answer:

the knee extensors must exert 15.87 N

Explanation:

Given the data in the question;

mass m = 4.5 kg

radius of gyration k = 23 cm = 0.23 m

angle ∅ = 30°

∝ = 1 rad/s²

distance of 3 cm from the axis of rotation at the knee r = 3 cm = 0.03 m

using the expression;

ζ = I∝

ζ = mk²∝

we substitute

ζ = 4.5 × (0.23)² × 1

ζ  = 0.23805 N-m

so

from; ζ = rFsin∅

F = ζ / rsin∅

we substitute

F = 0.23805 / (0.03 × sin( 30 ° )

F = 0.23805 / (0.03 × 0.5)

F F = 0.23805 / 0.015

F = 15.87 N

Therefore, the knee extensors must exert 15.87 N

7 0
3 years ago
A temperature of 34 fereheight is equal to blank kelvin
Oksanka [162]
247.11 Kelvin, you have to convert the 34 Fahrenheit to get to the answer that you need.
5 0
4 years ago
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2.15 Un móvil en trayectoria rectilinea ocupa las posiciones indicadas en la tabla para cada minuto:
inna [77]
To make sure I don’t has 35 012345 bishops
5 0
3 years ago
An electron moves through a uniform electric field E = (2.00î + 5.40ĵ) V/m and a uniform magnetic field B = 0.400k T. Determine
EleoNora [17]

Answer:a=1.75\times 10^{21}\left ( 2\hat{i}5.08\hat{j}\right )

Explanation:

Given

Electric Field \vec{E}=2\hat{i}+5.4\hat{j}

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velocity \vec{v}=8\hat{i} m/s

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Force on a charge Particle moving in Magnetic Field

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a=\frac{e\left [ \vec{E}+\left ( \vec{v}\times \vec{B}\right )\right ]}{m}

a=\frac{1.6\times 10^{-19}\left [ 2\hat{i}+5.4\hat{j}+\left ( 8\hat{i}\times 0.4\hat{k}\right )\right ]}{9.1\times 10^{-31}}  

a=1.75\times 10^{21}\left ( 2\hat{i}+5.08\hat{j}\right )\ m/s^2

7 0
3 years ago
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