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3 years ago

6

In general, how does precipitation in Washington, D.C., change between August and October? a. It increases b. It stays steady c.

It decreases d. It decreases and then increases

1 answer:

Firdavs [7]3 years ago

7 0

I’m sorry wish I could help

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A group of friends wants to go to the amusement park. they have no more than $405 to spend on parking and admission. parking is

lakkis [162]

$20+38.50x \leq 405$

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1 year ago

Write a let statement, an equation, solve: Jeremy is 14 years old. This is 4 1/2 years more than half his sisters age. How old i

Art [367]

J = 14
J = 1/2S + 4 1/2

14 = 1/2S + 9/2....multiply everything by 2 to get rid of fractions
28 = S + 9
28 - 9 = S
19 = S

check...
14 = 1/2S + 9/2......S = 19
14 = 1/2(19) + 9/2
14 = 9 1/2 + 9/2
14 = 19/2+ 9/2
14 = 28/2
14 = 14 (correct)

so the sister is 19 <===

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2 years ago

2÷1/3= how do you solve 1/3 of cherries divided equally between two people

sergejj [24]

Make the two 2/1 and make the 1/3 a 3/1. Your equation should be 2/1 x 3/1, then you must simplify your answer.

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2 years ago

Read 2 more answers

The magnitude of an earthquake is calculated using the Richter Scale, M=log I/io , where I0 is the threshold intensity and the i

marysya [2.9K]

Answer:

The answer is <u><em>log(980)! :)</em></u>

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2 years ago

Answer. it fast please

mojhsa [17]

Answer:

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{15}$

Step-by-step explanation:

Given

$(\frac{6}{10})^3 * (\frac{5}{9})^2$

Required

Solve:

$(\frac{6}{10})^3 * (\frac{5}{9})^2$

Simplify 6/10

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = (\frac{3}{5})^3 * (\frac{5}{9})^2$

Express 9 as 3^2

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = (\frac{3}{5})^3 * (\frac{5}{3^2})^2$

Apply law of indices

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{3^3}{5^3}* \frac{5^2}{(3^2)^2}$

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{3^3}{5^3}* \frac{5^2}{3^4}$

Express as a sing;e fraction

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{3^3*5^2}{5^3*3^4}$

Apply law of indices:

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{5^{3-2}*3^{4-3}}$

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{5^1*3^1}$

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{5*3}$

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{15}$

5 0

2 years ago