The name of the acid is Bromous acid and the Formula of the acid is HBrO₂.
<h3>What is Acids ? </h3>
Acids is defined as substances that is able to donate a proton or hydrogen ion to other substance. Acids acts as proton donor.
<h3>What is Oxoacids ? </h3>
An oxoacids is an acids that contains oxygen. It is also called oxyacids or ternary acids. Oxoacids are the acids of oxoanions.
If anion name contains the suffix ‘ate’ then replace ‘ate’ with ‘ic’.
If anion name contains the suffix ‘ite’ then replace ‘ite’ with ‘ous’.
Given anion is bromite. Formula of bromite is BrO₂⁻. It is an oxoanion.
Now write the name of acid. Here anion name contains the suffix ite so replace the ‘ite’ of bromite with ‘ous’.
The name of the acid is Bromous acid.
Formula of the acid is HBrO₂.
Thus from the above conclusion we can say that The name of the acid is Bromous acid and the Formula of the acid is HBrO₂.
Learn more about Oxoacids here: brainly.com/question/21795128
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A magnesium atom is a neutral atom where the number of protons and electrons are the same. A magnesium ion has a positve 2 charge since it will lose two of its electrons when it undergoes ionic bonding. Since it's the same element it will still have the same amount of 12 protons. For isotopes of magnesium, they will have differing amounts of neutrons and thus a difference in the mass number since neutrons have a mass of about 1
<h3>
Answer:</h3>
1.69 g Mg₃N₂
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
<u>Stoichiometry</u>
- Using Dimensional Analysis
- Reactions RxN
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
[RxN - Unbalanced] Mg + N₂ → Mg₃N₂
[RxN - Balanced] 3Mg + N₂ → Mg₃N₂
[Given] 1.22 g Mg
[Solve] grams Mg₃N₂
<u>Step 2: Identify Conversions</u>
[RxN] 3 mol Mg → Mg₃N₂
[PT] Molar Mass of Mg - 24.31 g/mol
[PT] Molar Mass of N - 14.01 g/mol
Molar Mass of Mg₃N₂ - 3(24.31) + 2(14.01) = 100.95 g/mol
<u>Step 3: Stoich</u>
- [DA] Set up:

- [DA] Multiply/Divide [Cancel out units]:

<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
1.68873 g Mg₃N₂ ≈ 1.69 g Mg₃N₂