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faltersainse [42]
3 years ago
7

Which of the above electron dot diagrams is wrong and why?

Chemistry
2 answers:
Firlakuza [10]3 years ago
8 0

Answer:here is ur answer...

Explanation:4)Oxygen O because it is supposed to have 6 valence electrons. .

Elodia [21]3 years ago
5 0

Answer:

Oxygen, it's supposed to have six valenge electrons.

Explanation:

Count the dots on the oxygen atom, you'll see seven, but there's supposed to be six.

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The "correct" mass of the cylinder had been previously determined to be 27.20 grams. What was the percent error on his first wei
Paraphin [41]

Answer:

Percent error =  - 8.1 %

Explanation:

Given data:

Actual mass = 27.20 g

Theoretical mass = 25.01 g

Percent error = ?

Solution:

Formula:

Percent error = theoretical value- actual value/ actual value × 100

Now we will put the values in formula.

Percent error =   25.01 - 27.2 / 27.2 × 100

Percent error = -2.19 / 27.2 × 100

Percent error = -0.081  × 100

Percent error =  - 8.1 %

5 0
3 years ago
The unit "troy ounce" is often used for precious metals such as gold (Au) and platinum (Pt) (1 troy ounce= 31.103 g). (a) A gold
frez [133]

Answer:

Explanation:

a) 1 troy ounce is equal to 31.103 g

2.41 troy ounce is equal to 2.41 x 31.103 g

= 74.958 g

b) 1  ounce = 1 / 16 lb = 1/16 x 453.6 g = 28.35 g.

1 troy ounce = 31.103 g

so 1 troy ounce is heavier than 1 ounce.

8 0
3 years ago
A partir de lo propuesto por Bohr en 1913, que postulado es correcto:
TEA [102]

Answer:

Primer postulado:

Así Bohr asumió que el átomo de hidrógeno puede existir solo en ciertos estados discretos, los cuales son denominados estados estacionarios del átomo. En el átomo no hay emisión de radiación electromagnética mientras el electrón no cambia de órbita.

Explanation:

4 0
3 years ago
Why did rutherford conclude from his gold foil experiment that an atom is mostly comprised of empty space?
Nady [450]
'cause many alpha-particle goes without any deflection........
6 0
3 years ago
If 1.02 g of nickel reacted with 750. mL of 0.112 M hydrobromic acid, how much of each will be present at the end of the reactio
kati45 [8]

Answer:

35.1% is percent yield

Explanation:

<em>Full question: Assume no volume change.  If you formed 0.0910 atm of gas, what is the percent yield?</em>

<em />

The reaction that is occurring is:

Ni + 3HBr → NiBr₃ + 3/2H₂(g)

First, we will determine moles of Ni and HBr to determine limiting reactant and theoretical yield

Using ideal gas law, we can determine the moles of hydrogen formed. Thus, we can find percent yield:

<em>Moles Ni (Molar mass: 58.69g/mol):</em>

1.02g * (1mol / 58.69g) = 0.01738moles Ni

<em>Moles HBr:</em>

0.750L * (0.112mol/L) = 0.084 moles of HBr.

For a complete reaction of the 0.084 moles of HBr you need:

0.084mol HBr * (1 mole Ni / 3 moles HBr) = 0.028 moles of Ni.

As there are just 0.01738 moles of Ni, the Ni is limiting reactant. Assuming a theoretical yield, moles of H₂ produced are:

0.01738moles Ni * (3/2 H₂ / 1 mol Ni) = 0.02607 moles H₂

Now, moles of H₂ produced are:

PV = nRT

PV/RT = n

<em>Where P is pressure (0.0910atm)</em>

<em>V is volume (2.50L)</em>

<em>R is gas constant (0.082atmL/molK)</em>

<em>T is absolute temperature in Kelvin (30°C + 273.15 = 303.15K)</em>

<em>And n are moles</em>

PV/RT = n

0.0910atm*2.50L/0.082atmL/molK*303.15K = n

0.00915 moles = n

<em />

And percent yield (Produced moles / Theoretical moles * 100) is:

0.00915 moles / 0.02607moles =

<h3>35.1% is percent yield</h3>
8 0
2 years ago
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