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Schach [20]
3 years ago
15

Solve equation please!! :) 10 points

Mathematics
2 answers:
Reil [10]3 years ago
7 0

3(x-3)-15 = 0

3x-9-15 = 0

3x - 24 = 0

3x = 24

x = 34/3

x = 8


dimulka [17.4K]3 years ago
3 0
3(x-3)-15 = 0
3(x-3) = 15
3x-9 = 15
3x = 24
x = 8
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\bf \begin{array}{llll}&#10;tan(\alpha)=-\cfrac{80}{15}\qquad II\\\\&#10;x=-15\\&#10;y=8\\&#10;r=17&#10;\end{array} \qquad \qquad &#10;\begin{array}{llll}&#10;cos(\beta)=\cfrac{5}{6}\qquad I\\\\&#10;x=5\\&#10;y=\sqrt{11}\\&#10;r=6&#10;\end{array}\\\\&#10;-----------------------------\\\\&#10;sin({{ \alpha}} + {{ \beta}})=sin({{ \alpha}})cos({{ \beta}}) + cos({{ \alpha}})sin({{ \beta}})&#10;\\\\\\&#10;sin({{ \alpha}} + {{ \beta}})=\cfrac{8}{17}\cdot \cfrac{5}{6}+\cfrac{-15}{17}\cdot \cfrac{\sqrt{11}}{6}\implies \cfrac{40-15\sqrt{11}}{102}



\bf cos({{ \alpha}} + {{ \beta}})= cos({{ \alpha}})cos({{ \beta}})- sin({{ \alpha}})sin({{ \beta}})&#10;\\\\\\&#10;\cfrac{-15}{17}\cdot \cfrac{5}{6}-\cfrac{8}{17}\cdot \cfrac{\sqrt{11}}{6}\implies \cfrac{-75-8\sqrt{11}}{102}





\bf tan({{ \alpha}} + {{ \beta}}) = \cfrac{tan({{ \alpha}})+ tan({{ \beta}})}{1- tan({{ \alpha}})tan({{ \beta}})}&#10;\\\\\\&#10;tan({{ \alpha}} + {{ \beta}}) = \cfrac{-\frac{8}{15}+\frac{\sqrt{11}}{5}}{1-\left( -\frac{8}{15}\cdot \frac{\sqrt{11}}{5} \right)}\implies &#10;\cfrac{\frac{-8+3\sqrt{11}}{15}}{1+\frac{8\sqrt{11}}{75}}&#10;\\\\\\&#10;tan({{ \alpha}} + {{ \beta}}) =\cfrac{\frac{-8+3\sqrt{11}}{15}}{\frac{75+8\sqrt{11}}{75}}\implies \cfrac{-8+3\sqrt{11}}{15}\cdot \cfrac{75}{75+8\sqrt{11}}&#10;\\\\\\&#10;

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