12x + (-3y) + 4x + (-z)
12 (3) + -3 (13) + 4 (3 ) + (-5)
36 + -39 + 12 + (-5)
36 + 12 -39 - 5
48 - 44
4
W=15 no
W= 21 no
W= 1 Yes
If im right the question is just asking which variable is less than 15.
so the only variable that is less than 15 is 1.
36/3=12
12/6=2
2x3=6
so first box is 12, second is 2, last one is 3
Jeremy can choose his outfit in following ways:
2 ways to select a shirt
2 ways to select a pant
2 ways to select socks
3 ways to select the footwear.
Total number of ways to select the dress = 2 x 2 x 2 x 3 = 24 ways
Jeremy will select an outfit that includes flip-flops, argyle socks and denim pants. The shirt is not specified, so the shirt can be any.
So there are 2 ways to select a shirt, 1 way to select the pant, socks and footwear. So Jeremy can select the desired outfit in 2 ways.
Thus, the probability that Jeremy will select an outfit that includes flip-flops, argyle socks and denim pants = 2/24 = 1/12
For the "system" to function, we require that
occurs (i.e. the event that either
or
function properly). This occurs with probability
but since
and
are independent,
We're given that
and
, so
If
, then
