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3 years ago

Will mark you BRAINLIEST!

Mathematics

2 answers:

attashe74 [19]3 years ago

8 0

Take the triangle as,

→ AB/AD = BC/ED

→ x/x+9 = 1/9

Now by using cross products,

→ 9 × x = 1(x+9)

→ 9x = x+9

Now subtract x from both sides,

→ 9x-x = x+9-x

→ 8x = 9

Then divide by 8 from both sides,

→ 8x/8 = 9/8

→ x = 9/8

So, the value of x is 9/8.

valentinak56 [21]3 years ago

7 0

Answer:

x = 9/8

Step-by-step explanation:

The triangles are similar so we can use ratios to solve

AB BC

---- = -----------

AD ED

x 1

---- = -----------

x+9 9

Using cross products

9*x = 1(x+9)

9x = x+9

Subtract x from each side

9x-x = x+9-x

8x = 9

Divide by 8

8x/8 = 9/8

x = 9/8

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Mary decided to bake a cake for her little sister. She needs 16 oz of milk but her measuring jug is not showing her what she nee

algol13

Recall the relation:

8 oz =1 cup

so,

1 oz = 18cup

Therefore,

16 oz = 168cup

= 2 cups

Hence, she should measure 2 cups to get 16 oz.

3 0

3 years ago

A researcher compares the effectiveness of two different instructional methods for teaching physiology. A sample of 178 students

xxTIMURxx [149]

Answer:

critical value = 1.645

The 90% confidence interval = ( -22.62, -17.58)

Step-by-step explanation:

Given that:

the sample size $n_1$ = 178

the sample size $n_2$ = 226

the sample mean $\overline x_1$ = 54.4

the sample mean $\overline x_2$ = 74.5

population standard deviation $\sigma_1$ = 18.58

population standard deviation $\sigma_2$ = 9.52

level of significance ∝ = 1 - 0.90 = 0.10

The critical value for $Z_{\alpha/2} = Z _{0.10/2} = Z_{0.005}$ is 1.645

For the construction of our confidence interval, we use 90% since that is used to find the critical value.

∴

The margin of error = $Z \times\sqrt{\dfrac{\sigma_1^2}{n_1} + \dfrac{\sigma_2^2}{n_2}}$

$1.645 \times\sqrt{\dfrac{18.58^2}{178} + \dfrac{9.52^2}{226}}$

$1.645 \times\sqrt{\dfrac{345.2164}{178} + \dfrac{90.6304}{226}}$

$1.645 \times\sqrt{2.34042}$

$\simeq$ 2.52

The lower limit = $( \overline x_1 - \overline x_2) - (M.O.E)$

= ( 54.4-74.5) - (2.52)

= -20.1 - 2.52

= -22.62

The upper limit = $( \overline x_1 - \overline x_2) + (M.O.E)$

= ( 54.4-74.5) + (2.52)

= -20.1 + 2.52

= -17.58

The 90% confidence interval = ( -22.62, -17.58)

6 0

3 years ago

Pleeeeease help me!!!

cricket20 [7]

Hello!

We solve this algebraically

y + 6 = 3/2(x - 4)

We distribute the 3/2

y + 6 = 3/2x - 6

If you work with decimals easier we can make 3/2 into a decimal

y + 6 = 1.5x - 6

Add 6 to both sides

y + 12 = 1.5x

subtract y from both sides

1.5x + -y = 12

Hope this helps!

8 0

3 years ago

Hi help me for vbucks

Leokris [45]

D. 44

4.5•2=9
9•3.14=28.26
28.28 rounds down to 28cm

11.5•2=23
23•3.14=72.22
72.22 rounds down to 72cm
72-28=44

8 0

3 years ago

Jacqueline's clock strikes every 15 minutes, how many times does it strike in a weak?

Ilia_Sergeevich [38]

It would strike <span>672 times. To figure this out all you would do is look up how many minutes is in a week and the divide that number by 15. Hope this helps!</span>

5 0

3 years ago

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