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Serga [27]
2 years ago
10

PLEASE PLEASE PLEASE HELP!!

Mathematics
1 answer:
Ivanshal [37]2 years ago
4 0
Problem 1) The triangles are similar because of the AA (angle angle) Similarity Theorem. The first A is the pair of congruent 39 degree angles. The second pair is unmarked, but look at where the triangles meet. They form a pair of vertical angles which are congruent. So we have two pairs of congruent angles allowing us to use the AA Similarity Theorem.

-----------------------------

Problem 2) We can use the SAS (Side Angle Side) Similarity Theorem to prove that these two triangles are similar. The angles are congruent. They are both 29 degrees. So that checks off the "A" portion of SAS. Then notice how the bottom sides are 32 and 64 for the small and large triangle respectively. They form the ratio 32/64 = 1/2, ie the smaller triangle's side is 1/2 as long as the longer counter part. Similarly, 8/16 = 1/2 as well. The ratio is constant at 1/2. This allows us to use the other "S" portions of SAS. 
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HELP! PLEASE! I really need help with this question!
LekaFEV [45]

Answer:

They are at the same height at 1.13 seconds.

Step-by-step explanation:

Remark

The rockets are at the same height when  f(x) = g(x) [see below] are the same. So you can equate them.

Givens

f(x) = - 16x^2 + 74x + 9

g(x) = -16x^2 + 82x              I have changed this so you don't have 2 f(x)s

Solution

  • f(x) = g(x)
  • -16x^2 + 74x + 9 = -16x^2 + 82x                        Add:  16x^2 to both sides
  • -16x^2+16x^2+74x + 9 = -16x^2+16x^2 + 82x   Combine terms
  • 74x + 9 = 82x                                                     Subtract 74x from both sides
  • 74x - 74x + 9 = 82x - 74x                                  Combine
  • 9 = 8x                                                                 Divide by 8
  • 9/8 = 8x/8
  • x = 1 1/8                                                              Convert to decimal
  • x = 1.125
  • x = 1.13  [rounded]


6 0
3 years ago
The box plots show the weights, in pounds, of the dogs in two different animal shelters.
zimovet [89]

*see attachment below for the box plots that is being referred to

Answer:

*The median weight for shelter A is greater than that for shelter B

*The data for shelter B are a symmetric data set

Step-by-step explanation:

Let's take each stated option and examine the box plot to see which is TRUE or NOT.

OPTION 1: "The median weight for shelter A is greater than that for shelter B."

The median for shelter A = 21,

Median for shelter B = 18

Median weight for shelter A (21) is greater than that for shelter B.

This statement in this option is TRUE.

OPTION 2: "The median weight for shelter B is greater than that for shelter A."

Median for B (18) < median of A (21)

This statement in option is NOT TRUE.

OPTION 3: "The data for shelter A are a symmetric data set."

This is NOT TRUE because the length of both whiskers are unequal and also, the box is not divided equally. One side is longer than the other.

OPTION 4: "The data for shelter B are a symmetric data set."

This is TRUE because the length of both whiskers are relatively equal, and also, the rectangular box is divided equally.

OPTION 5: "The interquartile range for shelter A is 8"

This is NOT TRUE.

IQR = Q3-Q1

IQR for shelter A is approximately  = 28-17 = 11

5 0
3 years ago
How many minutes are in 5.5 days
Hatshy [7]
There are 7,920 minutes in 5.5 days

60minutes in an hour
24hours in a day

60 times 24 times 5.5 = 7,920
7 0
3 years ago
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Dafna1 [17]

Answer:

B. 2nd Table

Step-by-step explanation:

3 0
3 years ago
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the function y =³√-x – 3 is graphed only over the domain of {x | –8 &lt; x &lt; 8}. what is the range of the graph? a). {y | –5
Fittoniya [83]
y=\sqrt[3]{-x}-3\ and\ x\in(-8;\ 8)\\\\subtitute\ x=-8\ and\ x=8\ to\ the\ equation:\\\\y=\sqrt[3]{-(-8)}-3=\sqrt[3]8-3=2-3=-1\\\\y=\sqrt[3]{-8}-3=-2-3=-5\\\\Answer:\boxed{\{y|-5 \ \textless \  y \ \textless \  -1\}}\to\fbox{b.}
7 0
3 years ago
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