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3 years ago

How will the graph of the equations in a system appear if the system has no solution?

Mathematics

1 answer:

Maru [420]3 years ago

8 0

They will appear as parallel lines

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How do I solve for x since the triangles are similar?

Llana [10]

A line that is parallel to a side and intersects the other two siddes divides the sides proportionally.

Set up the proportion
2/x+1 = x/x+6
Multiply means and extremes
2x+12= x^2+ x
Solve to get your answer.

3 0

3 years ago

* 3) What is 40ab in expanded form?

professor190 [17]

Answer:

$40*a*b$

Step-by-step explanation:

40ab is 40 multiplied by a multiplied by b

4 0

3 years ago

2 points

miskamm [114]

The x - intercept of 5x - 3y = 15 is (3, 0)

The y -intercept of 5x - 3y = 15 is (0, -5)

<h3>Solution:</h3>

Given equation is 5x - 3y = 15

To find: x - intercept and y -intercept

The x intercept is the point where the line crosses the x axis. At this point y = 0

The y intercept is the point where the line crosses the y axis. At this point x = 0.

Finding x - intercept:

To find the x intercept using the equation of the line, plug in 0 for the y variable and solve for x

So put y = 0 in given equation

5x - 3(0) = 15

5x = 15

x = 3

So the x - intercept is (3, 0)

Finding y - intercept:

To find the y intercept using the equation of the line, plug in 0 for the x variable and solve for y

So put x = 0 in given equation

5(0) - 3y = 15

-3y = 15

y = -5

So the y - intercept is (0, -5)

5 0

3 years ago

the seating capacity of basketball stadium is 5782 the seats are arranged in 24 sections of the same size any seats over from th

notsponge [240]

5782/24=240 since we round down to s whole.

Multiply again by 24.
240*24=5760

There are 5782-5760=22 priority seats.

The correct answer is 22.

3 0

3 years ago

The sample consisted of 50 night students, with a sample mean GPA of 3.02 and a standard deviation of 0.08, and 25 day students,

bulgar [2K]

Answer: The test statistic is t= -0.90.

Step-by-step explanation:

Since we have given that

n₁ = 50

n₂ = 25

$\bar{x_1}=3.02\\\\\bar{x_2}=3.04\\\\\sigma_1=0.08\\\\\sigma_2=0.06$

So, s would be

$s=\sqrt{\dfrac{n_1\sigma_1^2+n_2\sigma_2^2}{n_1+n_2-2}}\\\\s=\sqrt{\dfrac{50\times 0.08^2+25\times 0.06^2}{50+25-2}}\\\\s=0.075$

So, the value of test statistic would be

$t=\dfrac{\bar{x_1}-\bar{x_2}}{s(\dfrac{1}{n_1}+\dfrac{1}{n_2})}\\t=\dfrac{3.02-3.04}{0.074(\dfrac{1}{50}+\dfrac{1}{25})}\\\\t=\dfrac{-0.04}{0.074(0.02+0.04)}\\\\t=\dfrac{-0.04}{0.044}\\\\t=-0.90$

Hence, the test statistic is t= -0.90.

7 0

3 years ago