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3 years ago

Checking account a has a service fee of $3 and a per check fee of $0.02 while checking account b charges a monthly fee of $2

Mathematics

2 answers:

bonufazy [111]3 years ago

7 0

Answer:

100 checks :)

Alecsey [184]3 years ago

6 0

Idk how to answer this

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At a carnival, 700 tickets were sold for a total

Diano4ka-milaya [45]

Answer:

The adult tickets are 400 and the children tickets are 300.

Step-by-step explanation:

Given:

At a carnival, 700 tickets were sold for a total amount of $5500. An adult ticket cost $10 and a children's ticket cost $5.

Now, to find the number of adult tickets and the number of children's tickets sold.

Let the number of adult tickets be $x.$

And let the number of children tickets be $y.$

So, the total number of tickets sold:

$x+y=700\\\\y=700-x\ \ \ ....(1)$

Now, the total amount of tickets:

$x(10)+y(5)=5500$

Substituting the value of $y$ from equation (1):

$x(10)+(700-x)(5)=5500\\\\10x+3500-5x=5500\\\\5x+3500=5500$

Subtracting both sides by 3500 we get:

$5x=2000$

Dividing boths sides by 5 we get:

$x=400.$

The number of adult tickets = 400.

Now, substituting the value of $x$ in equation (1) we get:

$y=700-x\\\\y=700-400\\\\y=300.$

The number of children tickets = 300.

Therefore, the adult tickets are 400 and the children tickets are 300.

8 0

3 years ago

A circle has a circumference of 150 meters. What is the measure of its radius? Round

kupik [55]

Answer:

$2\pi \times \: r = 150 \\ 6.2831r = 150 \\ \frac{6.2831r}{6.2831} = \frac{150}{6.2831} \\ r = 23.87cm$

4 0

3 years ago

Read 2 more answers

The lengths, in minutes, of the movies currently showing at a movie theater are shown in the data set. Create a histogram

alexdok [17]

Answer:

See Explanation

Step-by-step explanation:

The question is incomplete, as the required lengths are not given.

I will use the following data set to answer the question.

$Dataset: 35, 51, 39, 42, 68, 62, 32, 59$

First, is to determine the range of the dataset

$Range = Highest - Least$

$Range = 68 - 32$

$Range = 36$

Next, we will make use of 4 classes. So, we divide range by 10 to get the number of class. 10 represents the interval

$Class= Range/10$

$Class = 36/10$

$Class = 3.6$

$Class \approx 4$

So, we use 4 classes

Plot the frequency distribution table as follows:

$\begin{array}{ccc}{Intervals} & {Observations} & {Frequency} & {31-40} & {32,35,39} & {3} & {41-50} & {42} & {1} & {51-60} & {51,59} & {2} & {61-70} & {62,68} & {2}\ \end{array}$

See attachment for histogram

5 0

3 years ago

Need help on answering number 16.

g100num [7]

Boom ha do boop bam pow oof big dude oof mousse oof sorry I couldn’t help ya son

6 0

3 years ago

What is the lcm of xy(x+1) and x(x+2)

cestrela7 [59]

$xy(x+1)=x\cdot y\cdot (x+1)\\x(x+2)=x\cdot (x+2)\\\\\text{lcm}(xy(x+1),x(x+2))=x\cdot y \cdot (x+1)\cdot (x+2)=xy(x+1)(x+2)$

8 0

3 years ago