Compound A will be 2-chloro-butane which in the presence of sodium methoxide will undergo the elimination of the halogen with a hydrogen from the neighboring atom carbon (not the one with which the halogen in bound), which have less hydrogen atoms, forming the trans-2-butene.
Answer:
2-chlorobutane.
Explanation:
Hello,
In this case, the treatment of the substance A with sodium methoxide to yield trans-2-butene stands for a dehydrohalogenation in the presence of a strong base (the sodium methoxide), such chemical reaction is undergone by alkyl halides, in this case with chlorine, based on its molecular formula. In such a way, on the attached picture, you will find both the structure of the 2-chlorobutane and its chemical reaction to yield the trans-2-butene throughout the usage of sodium methoxide.
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Answer : The value of 'R' is
Solution : Given,
At STP conditions,
Pressure = 1 atm
Temperature = 273 K
Number of moles = 1 mole
Volume = 22.4 L
Formula used :
where,
R = Gas constant
P = pressure of gas
T = temperature of gas
V = volume of gas
n = number of moles of gas
Now put all the given values in this formula, we get the values of 'R'.
Therefore, the value of 'R' is .
Answer:
a. the negative ends of water molecules surround the positive ions.
Explanation:
Ionization reaction is defined as the reaction in which an ionic compound dissociates into its ions when dissolved in aqueous solution.
Thus,
When the ionic compound dissociates, the cation which is positively charged gets attracted to the oxygen (Negative ends) which is present in the water. The anion which is negatively charged gets attracted to the hydrogen (Positive ends) of the water.
Hence, the correct option is:- a. the negative ends of water molecules surround the positive ions.