Answer:
3 m/s²
Explanation:
Sum of forces in the x direction:
∑F = ma
68 N − 23 N = (15 kg) a
a = 3 m/s²
Answer:
2.54 μA
Explanation:
The current I in the wire is I = ∫∫J(r)rdrdθ
Since J(r) = Br, in the radial width of 13.1 μm, dr = 13.1 μm. r = 1.50 mm. We have a differential current dI. We remove the first integral by integrating dθ from θ = 0 to θ = 2π.
So, dI = J(r)rdrdθ ⇒ dI/dr = ∫J(r)rdθ = ∫Br²dθ = Br²∫dθ = 2πBr²
Now I = (dI/dr)dr evaluate at r = 1.50 mm = 1.50 × 10⁻³ m and dr = 13.1 μm = 0.013 mm = 0.013 × 10⁻³ m
I = (2πBr²)dr = 2π × 2.34 × 10 A/m³ × (1.50 × 10⁻³ m)² × 0.013 × 10⁻³ m = 2544.69 × 10⁻⁹ A = 2.54 × 10⁻⁶ A = 2.54 μA
True it help support reglions
Answer:
All objects free fall at the same rate regardless of their mass. Because the 9.8 N/kg gravitational field at Earth's surface causes a 9.8 m/s/s acceleration of any object placed there, we often call this ratio the acceleration of gravity.
Explanation:
Newton's Second Law, if I remember right.
Answer:
True.
Explanation:
Adding a non - volatile solute to solvent, decreases the tendency for water molecules to evaporate into gas phase i.e these non - volatile solute particles obstruct or reduce the rate of evaporation. Few water molecules in the vapour.
Therefore, Adding a nonvolatile solute to a solution decreases the vapor pressure of the solution while
Vapor pressure is a measurement of the likelihood of the molecules of a pure solvent to change from the liquid to the vapor phase.
Using Raoult's Law:
Psol = Xsolv * P°solv
where:
Psol = the vapor pressure of the solvent above the solution,
Xsolv = the mole fraction of the solvent in the solution, and
P°solv = the vapor pressure of the pure solvent.