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zaharov [31]
4 years ago
5

In this lab, you will use a cart and a track to explore Newton’s second law of motion. You will vary two different variables and

determine how each one affects how quickly the cart moves along the track. In the space below, write a scientific question that you can answer by doing this experiment.
Physics
1 answer:
lutik1710 [3]4 years ago
6 0

Questions that can be answered by doing the experiment and making observations scientifically:

1).  How long will it take to perform the complete experiment ?

2). Will it be daytime or night-time when the experiment begins ?

3). What will be the range of outdoor temperatures during the experiment ?

4). How many times will progress of the experiment be suspended in order to take phone calls ?

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Charra [1.4K]
Absolute dating and relative dating are both used commonly to determine the age of fossils. Absolute dating gives the exact date and chronological order to which the fossil lived. They do this by looking at the surrounding ground and using the carbon to find out how old it is. Relative dating is pretty similar to this except it uses carbon dating which is a way of finding the approximate age of the fossil. They do this by looking at the layers of the earth and making an assumption as to how old it is.
6 0
3 years ago
Read 2 more answers
If 4.5×105kg of emergency cooling water at 10 ∘C are dumped into a malfunctioning nuclear reactor whose core is producing energy
Stella [2.4K]

Answer:

\Delta t= 2962.395\,s\,(49.373\,min)

Explanation:

Let assume that cooling water works under a pressure of 1 atmosphere. The time required to boil half of the water is determined by the First Law of Thermodynamics:

\dot Q \cdot \Delta t = m \cdot [c_{p,w}\cdot (T_{2}-T_{1})+h_{fg}]

\Delta t = \frac{m\cdot [c_{p,w}\cdot (T_{2}-T_{1})+h_{fg}]}{\dot Q}

\Delta t = \frac{(2.25\times 10^{5}\,kg)\left[\left(4.186\,\frac{kJ}{kg\cdot ^{\textdegree}C} \right)\cdot (100\,^{\textdegree}C - 10\,^{\textdegree}C)+2256.5\,\frac{kJ}{kg} \right]}{200000\,kW}

\Delta t= 2962.395\,s\,(49.373\,min)

8 0
4 years ago
18. An electric dipole is completely inside a closed imaginary surface and there are no other charges. True or false: (a) The el
Zina [86]

Answer:

Explanation:

We shall apply Gauss's theorem to calculate the electric flux through a closed surface due to charge contained in side

Total charge inside surface = zero  

So total electric flux through closed surface will be zero.  

or electric flux going out = electric flux coming in  

(a) The electric field is zero everywhere on the surface.  True  

(b) The electric field is normal to the surface everywhere on the surface. - false

(c) The electric flux through the surface is zero. True  

(d) The electric flux through the surface could be positive or negative - false

(e) The electric flux through a portion of the surface might not be zero - True

6 0
3 years ago
Why earth have gravity​
enot [183]

Answer:

Because it has mass.

Explanation:

8 0
3 years ago
The free-electron density in a copper wire is 8.5×1028 electrons/m3. The electric field in the wire is 0.0520 N/C and the temper
meriva

Answer:

(a) 1.87 x 10⁻⁴ m/s

(b) 0.013V

Explanation:

(a) Drift speed, v_{d} , is the average velocity that a charged particle can have due to an electric field. For a given current, I, the drift velocity is given by;

v_{d} = \frac{I}{qnA}             ----------------(i)

Where;

q = amount of charge

n = free charge density

A = cross-sectional area of the wire

But current density, J, is the electric current per unit cross-section area. This  is also equal to the ratio of the electric field, E, to the resistivity, p, of the material of the wire. i.e

J = \frac{I}{A} = \frac{E}{p}

Equation (i) can then be written as follows;

v_{d} = \frac{J}{qn} = \frac{E}{qnp}

v_{d} = \frac{E}{qnp}      ---------------------(ii)

From the question;

E = 0.0520N/C

p = 1.72 x 10⁻⁸ Ωm

n = 8.5 x 10²⁸ electrons/m³

c = charge on electron = 1.9 x 10⁻¹⁹C

Substitute these values into equation (ii) as follows;

v_{d} = \frac{0.0520}{1.9*10^{-19} * 8.5*10^{28} * 1.72*10^{-8}}

v_{d} = 1.87 x 10⁻⁴ m/s

(b) The potential difference, V, is given by the product of the electric field and the distance, d, between the two points in the wire. i.e

V = E x d        [where d = 25.0cm = 0.25m]

V = 0.0520 x 0.25

V = 0.013V

4 0
3 years ago
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